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3 years ago

If we want to know the velocity that an object is traveling, we must know the

Physics

2 answers:

julia-pushkina [17]3 years ago

7 0

Answer:

direction and speed.

Explanation:

Serga [27]3 years ago

4 0

If my memory serves me well, if we want to know the velocity that an object is traveling, we must know the <span>direction and speed. Velocity includes two these points listed in the previous sentence which means the answer is D.</span>

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The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists obs

anygoal [31]

Answer:

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

$v = 4 m/s$

Now the centripetal acceleration of the sea lion is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{0.37}$

$a_c = 43.2 m/s^2$

as we know that

$g = 9.8 m/s^2$

so we have

$a = 4.41 g$

Now Percentage of this acceleration wrt maximum jet acceleration is given as

$P = \frac{4.41 g}{9g} \times 100$

$P = 49$ %

6 0

3 years ago

A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet

Serga [27]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = $0.27 J$

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm = 0.0591 m [Note 1 m = 100 cm ]

considering the formula above

$9.13 = k * 0.0591$ where k denotes torque

$k = 154.48\ N/m$

Energy Stored $= \frac{1}{2} k x^2$

$= \frac{1}{2} * 154.48 * (0.0591)^2$

$= 0.27J$

8 0

3 years ago

Use this free body diagram to help you find the magnitude of the force F1 needed to keep this block in static equilibrium 15.3 N

bija089 [108]

Do you have a picture of the diagram?

5 0

3 years ago

Suppose we wrap a string around the surface of a uniform cylinder of radius 38.0 cm that is supported by an axle passing through

liraira [26]

Answer:

Angular acceleration = 23.68 rad / s²

Explanation:

Given that,

acceleration = 9m/s²

Therefore acceleration of string is 9m/s²

since string is constant in length

cylinder of radius 38.0 cm = 0.38m

Angular acceleration = a / r

Angular acceleration = 9 / 0.38

= 23.68 rad / s²

Angular acceleration = 23.68 rad / s²

4 0

3 years ago

A 48.0-kg skater is standing at rest in front of a wall. By pushing against the wall she propels herself backward with a velocit

Kipish [7]

Answer:

F = 47.6 N

Explanation:

Newton's 2nd law can be expressed as the rate of change of the total momentum, respect of time, as follows:

$F = \frac{\Delta p}{\Delta t}$

So, in order to find the average force exerted by the skater on the wall, we can find the change in momentum due to the force exerted by the wall (which is equal and opposite to the one exerted by the skater), and divide it by the time interval , as follows:

$F_{wall} = \frac{\Delta p}{\Delta t} =\frac{(48.0 kg*(-1.06m/s)}{1.07s} = -47.6 N$

⇒ Fsk = 47.6 N (normal to the wall)

3 0

3 years ago