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Natali [406]
3 years ago
9

If we want to know the velocity that an object is traveling, we must know the

Physics
2 answers:
julia-pushkina [17]3 years ago
7 0

Answer:

direction and speed.

Explanation:

Serga [27]3 years ago
4 0
If my memory serves me well, if we want to know the velocity that an object is traveling, we must know the <span>direction and speed. Velocity includes two these points listed in the previous sentence which means the answer is D.</span>
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How do you move the decimal from megameters to meters?
Deffense [45]
The prefix "mega" means million.
Therefore
1 megameter = 10⁶ meters

That is,
1.0 megameter = 1,000,000.0 meters.

Answer:
The decimal is moved right by 6 places to convert a megameter to meters.
8 0
3 years ago
A 123-turn circular coil of radius 2.41 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi
klasskru [66]

Answer:

67.44 V

Explanation:

Number of turns N =123

Radius = 2.41 cm =0.0241 m

The magnetic field strength increases from 50.9 T to 96.3 T so change in magnetic field dB = 96.3-50.9=45.4 T

Time interval dt = 0.151 sec

We know that the induced emf e=-NA\frac{dB}{dt}

Area A=\pi r^2=3.14\times 0.0241^2=1.8237\times 10^{-3}m^2

Putting all these values in emf equation e=-123\times 1.8237\times 10^{-3}\times \frac{45.4}{0.151}=-67.44\ V here negative sign indicates that it opposes the cause due to which it is produced

8 0
3 years ago
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μC. They are separated by a distance of 0.241 m, and part
lesya [120]

Answer:

Charge of particle 2, q_2=-7.13\ \mu C

Explanation:

Given that,

Charge 1, q_1=3.11\ \mu C=3.11\times 10^{-6}\ C

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

F=k\dfrac{q_1q_2}{r^2}

q_2=\dfrac{Fr^2}{kq_1}

q_2=\dfrac{3.44\times (0.241)^2}{9\times 10^9\times 3.11\times 10^{-6}}

q_2=7.13\times 10^{-6}\ C

or

q_2=7.13\ \mu C

So, the magnitude of electric charge 2 is q_2=7.13\ \mu C. Since, the force is attractive then the magnitude of charge 2 must be negative.

5 0
3 years ago
How fast must a 350 gram softball be traveling in order to have a momentum of .600 kg
BartSMP [9]
Momentum is mass times velocity. So here we can just substitute in our givens and solve for velocity.

.600kg*m/s/.350kg=1.71m/s

Hope this helps! Thank you!
4 0
4 years ago
A 100-watt lightbulb uses 1 kilowatt-hour of electrical
Harlamova29_29 [7]

Answer:

Energy = 0.25 kilowatt-hour

Explanation:

Given the following data;

Power = 25 Watts

Time = 10 hours

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

To find the energy consumed;

Energy = power * time

Substituting into the formula, we have;

Energy = 25 * 10

Energy = 250 Watt-hour

To convert to kilowatt-hour, we would divide by 1000;

Energy = 250/1000

Energy = 0.25 kilowatt-hour

3 0
3 years ago
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