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Natali [406]
3 years ago
9

If we want to know the velocity that an object is traveling, we must know the

Physics
2 answers:
julia-pushkina [17]3 years ago
7 0

Answer:

direction and speed.

Explanation:

Serga [27]3 years ago
4 0
If my memory serves me well, if we want to know the velocity that an object is traveling, we must know the <span>direction and speed. Velocity includes two these points listed in the previous sentence which means the answer is D.</span>
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I Think its ABC

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he graph shows the distance (x) traveled by an aircraft traveling at constant velocity in corresponding time intervals (t). What
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The internal pressure on a bottle of soda is 5550 torr. the bottle cap is designed to withstand a pressure of 7.2 atm. (a) calcu
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2 years ago
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5.
uysha [10]

Answer:

<h3>U_{2}=4U_{1}</h3><h3>Explanation:</h3>

Let U1 and U2 be the gravitational potential energy of the first and second stone  respectively.

U1 is given by:

U_1 = (m)gh\\

and U2 is given by:

U_2 = (4m)gh  

therefore, comparing the energies we have:

\frac{U_2}{U_1} = \frac{(4m)gh}{(m)gh}= 4

therefore:

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5 0
3 years ago
A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach?
timofeeve [1]

Answer:

The height (h) will be: \frac{3}{4}R =h  

Explanation:

The scape speed equation is given by:

v_{scape}=\sqrt{\frac{2GM}{R}}

Now, the speed of the missile is

v_{missile}=\frac{1}{2}v_{scape}

v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}

Using the conservation of energy, we can find the maximu height of the missile.

E_{i}=E_{f}

\frac{1}{2}mv_{scape}^{2}-mgR =-mgh

\frac{1}{2}\frac{2GM}{4R}-gR =-gh

\frac{GM}{4R}-gR =gh

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

\frac{1}{4}gR-gR =-gh

\frac{1}{4}R-R =-h    

Therefore the height (h) will be:

\frac{3}{4}R =h    

I hope it helps you!

4 0
2 years ago
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