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algol13
3 years ago
6

If we increase the distance traveled when doing work , and keep all other factors the same, what will happen?

Physics
2 answers:
Dmitriy789 [7]3 years ago
5 0
D.increase the amount of work
Anna007 [38]3 years ago
3 0

Answer:

option (d)

Explanation:

Work done is defined as the product of force applied and the displacement.

If the distance traveled is more and force remains constant it means the work will increase.

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3 years ago
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Where is the potential energy equal to zero?
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Answer:

im sure your already past this but it's E.

Explanation:

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3 years ago
What is an unbalanced force
Butoxors [25]
There's no such thing as "an unbalanced force".

If all of the forces acting on an object all add up to zero, then we say that
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A group of forces is either balanced or unbalanced.  A single force isn't.
7 0
3 years ago
A cosmic ray (an electron or nucleus moving ar speeds close to the speed of light) travels across the Milky Way at a speed of 0.
Fiesta28 [93]

Answer:

Cosmic ray's frame of reference: 99,875 years

Stationary frame of reference: 501,891 years

Explanation:

First of all, we convert the distance from parsec into metres:

d=30,000 pc =9.26\cdot 10^{20} m

The speed of the cosmic ray is

v=0.98 c

where

c=3.0 \cdot 10^8 m/s is the speed of light. Substituting,

v=(0.98)(3.0\cdot 10^8)=2.94\cdot 10^8 m/s

And so, the time taken to complete the journey in the cosmic's ray frame of reference (called proper time) is:

T_0 = \frac{d}{v}=\frac{9.26\cdot 10^{20}}{2.94\cdot 10^8}=3.15\cdot 10^{12} s

Converting into years,

T_0 = \frac{3.15\cdot 10^{12}}{(365\cdot 24\cdot 60 \cdot 60}=99,875 years

Instead, the time elapsed in the stationary frame of reference is given by Lorentz transformation:

T=\frac{T_0}{\sqrt{1-(\frac{v}{c^2})^2}}

And substituting v = 0.98c, we find:

T=\frac{99,875}{\sqrt{1-(\frac{0.98c}{c})^2}}=501,891 years

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What is nucleic acid
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like dioxyribonucleic acid? if so then that's DNA


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