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3 years ago

Solve: 9(x^2+1/x^2) -9(x+1/x)-52=0

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer

x1 = −1.768

Step-by-step explanation:

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What is the slope of (2,-12), (18,15)

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

The slope of a line given two points $(x_0,y_0)$ and $(x_1,y_1)$ is

$m=\frac{y_1-y_0}{x_1-x_0}=\frac{15-(-12)}{18-2}=\frac{27}{16}$

7 0

3 years ago

2x+4y=6<br> 3x=12-6y<br> Solve by elimination

faltersainse [42]

Answer:

no solution

Step-by-step explanation:

2x + 4y = 6......reduces to x + 2y = 3

3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4

so now we have :

x + 2y = 3

x + 2y = 4

ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.

5 0

3 years ago

Read 2 more answers

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!