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Ivan
4 years ago
6

What is the oxidation number b in h3bo3?

Chemistry
1 answer:
Goryan [66]4 years ago
5 0
H is positive 1 and o is negative 2 so 3+b-6=0 and solve for b to get b=3
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A smaple of 1cm cuvette gives an absorbance reading of 0.558. if they absorptivity for this sample is 15000l/(mol.cm), what is t
Mazyrski [523]
To solve this problem, we use Beer's Law: A= ε.l.c
A is the absorbance- 0,558
<span>ε is</span> the molar absorptivity- is <span>15000 </span><span><span>L⋅mol-1</span><span>cm-1</span></span>
<span>l is </span>the length of the cuvette- 1 cm
<span>c is</span> the molar concentration

Applying the formula,
0,558= 15000 x 1 x c
0,558/15000= c
c= <span>3.72×<span>10⁻⁵ </span> <span>mol⋅L<span>⁻¹</span></span></span>
<span />
3 0
3 years ago
How many grams of Sodium will have the same number of atoms as 6 grams of Magnesium?
Ksivusya [100]

Answer:

92gm

Explanation:

Atomic mass of Mg=24g=1 mole of Mg

∴  24g =1 mole of Mg contain 6.022×10^23 atom 

∴  6gm contains 246.022×1023×6

                            =4×6.022×10^23 atoms

Now according to question, there are 6.022×1023 atoms of Na 

23gm of Na contains 6.022×10^23 atoms

∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm

3 0
3 years ago
The term gas is limited to those substances that exist in the gaseous state at
Assoli18 [71]
Physical change alters a given material without changing its chemical.
3 0
3 years ago
hEEEYYYY peeps! this is the same related question about another scientist with the cells, so yeaaaaaah...btw meh teacher also ma
ki77a [65]

Answer:

im pretty sure it is D

Explanation:

this is an old term for a microscopic organisms that included bacteria, protozoans, and very small animals

4 0
3 years ago
The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i
antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC

c = specific heat capacity of gold = 0.1291joules/gram^oC

m = mass of gold =15.71 g

Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram

Heat gained by gold = 2093.0621 Joules + 997.585 Joules

=3090.6471 joules

6 0
3 years ago
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