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Alex
3 years ago
11

An atom is the smallest identifiable unit of a compound true or false

Chemistry
1 answer:
notsponge [240]3 years ago
7 0
 False that  atom  is the smallest  identifiable  unit  of  a compound.

The   smallest   identifiable  unit  of   a compound  is  the    Element.  Element  is the one which  make up the  compound  and element  is made up by atoms.  Example  of element  is  oxygen  and  hydrogen  which  make  up water (H2O) which is  a compound.
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Ammonia (NH3) can be synthesized from nitrogen gas (N2) and hydrogen gas (H2) by the following reaction.
Advocard [28]

Answer:

                      %age Yield  =  66.05 %

Explanation:

                     In order to check the efficiency of a reaction the %age is calculated so that it can be concluded that either the conditions provided for certain reactions are favourable or not because at large scales reactions with greater %age yields are favoured as it results in high product quantity and hence, greater economical advantages.

                   The percent yield is given as;

                  %age Yield  =  Actual Yield / Theoretical Yield × 100

Putting values,

                   %age Yield  =  253 g / 383 g × 100

                   %age Yield  =  66.05 %

Hence, for the given reaction the success of the reaction is only 65% hence, steps can be made to improve this yield by modifying the reaction conditions.

6 0
3 years ago
A 45.0 mL sample of 0.020 M acetic acid (HC2H3O2) is titrated with 0.020 M NaOH.? Determine the pH of the solution after adding
White raven [17]

Answer:

Explanation:

CH₃COOH + NaOH = CH₃COONa + H₂O .

.02M

CH₃COOH  = CH₃COO⁻ + H⁺

C                       xC             xC

Ka = xC . xC / C = x² C

1.8 x 10⁻⁵ = x² . .02

x² = 9 x 10⁻⁴

x = 3 x 10⁻²

= .03

concentration of H⁺ = xC = .03 . .02

= 6 x 10⁻⁴ M , volume =  45 x 10⁻³ L

moles of H⁺  = 6 X 10⁻⁴  x 45 x 10⁻³

= 270 x 10⁻⁷ moles

= 2.7 x 10⁻⁵ moles

concentration of NaOH = .0200 M , volume = 35 x 10⁻³ L

moles of Na OH = 2 X 10⁻²  x 35 x 10⁻³

= 70 x 10⁻⁵ moles

=  

NaOH is a strong base so it will dissociate fully .

there will be neutralisation reaction between the two .

Net NaOH remaining = (70 - 2.7 ) x 10⁻⁵ moles

= 67.3 x 10⁻⁵ moles of NaOH

Total volume = 45 + 35 = 80 x 10⁻³

concentration of NaOH after neutralisation.= 67.3  x 10⁻⁵ / 80 x 10⁻³ moles / L

= 8.4125  x 10⁻³ moles / L

OH⁻ = 8.4125  x 10⁻³

H⁺ = 10⁻¹⁴ / 8.4125  x 10⁻³

= 1.1887 x 10⁻¹²

pH = - log (  1.1887 x 10⁻¹² )

= 12 - log 1.1887

= 12 - .075

= 11.925 .

4 0
3 years ago
Which of the following actions will not increase the rate at which a solid dissolves in
aliya0001 [1]

Answer:

O lowering the temperature of the system

5 0
3 years ago
If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial
Tems11 [23]

Answer:

0.0295M

Explanation:

As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.

You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.

That means you are diluting your solution 95.0mL / 35.0mL = 2.714 times.

And the concentration of SCN⁻ is:

0.0800M / 2.714 =

<h3>0.0295M </h3>

4 0
3 years ago
1. What is the electron configuration of bromine atom?
Ganezh [65]

Answer:

[Ar] 3d¹⁰ 4s² 4p⁵

Explanation:

........

7 0
2 years ago
Read 2 more answers
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