Question

What is the mass percent of nitrogen in lead (ii) nitrate (pb(no3)2)?

Answer 1

In order to calculate the mass percent of nitrogen in Pb(NO3)2, first, list the molar mass of all elements. 

Pb = 207.2 g/mol
N = 14 g/mol
O = 16 g/mol

Then, multiply each element to the number of each atom in the compound to get the mass contribution of each element, in this case:

Pb = (207.2 x 1) = 207.2
N = (14 x 2) = 28
O = (16 x 6) = 96

Add the resulting products to obtain the total molecular mass of the compound. This is equal to 331.2 g/mol. Finally, to get the mass percent of nitrogen, divide its mass contribution by the total molecular mass, as in, (28/331.2) x 100%. Thus, the mass percent of nitrogen in Pb(NO3)2 is 8.45%.