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2 years ago

A sound wave is an example of a

2 answers:

Studentka2010 [4]2 years ago

4 0

Longitudinal waves....
sounds propagates through moving waves of compression and ratification of a medium which allows longitudinal propagation

kap26 [50]2 years ago

4 0

I just did this test the answer is

b. longitudinal wave.

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In which direction does a convergent boundary move?

VladimirAG [237]

Answer:

Toward each other teehee merry christmas

Explanation:

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2 years ago

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Which of the following is a strength training option?

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Answer:

D. All of the above

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2 years ago

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If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V, the current flowing through the circ

dem82 [27]

Question 2.

A transmission system at a radio station consists of essentially the following devices:

1. An oscillator, which converts a direct current into a high-frequency alternating current.

2. A transmitting antenna, which sends out radio waves having the same frequency as the current supplied by the oscillator.

3. A microphone, which picks up the sound waves and converts them into a suitable electric current with the same pattern as the sound waves.

4. A modulator, which enables the waves produced by the antenna to “carry” the pattern of the sound waves picked up by the microphone.

The answer is C. Oscillator

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2 years ago

A Carnot engine operates between 1350 °F and 125 °F. If it rejects 55 Btu as heat, determine the work output.

ruslelena [56]

Answer:

C. $W = 115.12\,Btu$

Explanation:

Thermodynamically speaking, a Carnot engine represents an entirely reversible thermal process and its energy efficiency represents the maximum theoretical efficiency that thermal machines can reach. The efficiency of the ideal thermal process ( $\eta$ ), no unit, is:

$\eta = \left(1-\frac{T_{L}}{T_{H}} \right)$ (1)

Where:

$T_{L}$ - Temperature of the cold reservoir, measured in Rankine.

$T_{H}$ - Temperature of the hot reservoir, measured in Rankine.

If we know that $T_{H} = 1809.67\,R$ and $T_{L} = 584.67\,R$ , then the energy efficiency of the ideal thermal process is:

$\eta = 0.678$

By First Law of Thermodynamics, we calculate the work output:

$W = Q_{H}-Q_{L}$

$W = \frac{W}{\eta} -Q_{L}$ (By definition of efficiency)

$Q_{L} = \frac{W}{\eta}-W$

$Q_{L} = \left(\frac{1}{\eta}-1 \right)\cdot W$ (2)

Where:

$Q_{H}$ - Heat received by the engine, measured in Btu.

$Q_{L}$ - Heat rejected by the engine, measured in Btu.

$W$ - Work output, measured in Btu.

If we know that $\eta = 0.678$ and $Q_{L} = 55\,Btu$ , then the work output of the Carnot engine is:

$W = \frac{Q_{L}}{\frac{1}{\eta}-1 }$

$W = 115.807\,Btu$

The work output of the Carnot engine is 115.807 Btu. (Answer: C)

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2 years ago

"A circuit consists of a battery and two resistors connected in parallel. If the resistance in both resistors is doubled, and th

sveticcg [70]

Let's call R the value of the resistance of the two resistors. In the first situation, the resistors are connected in parallel, so their equivalent resistance is given by:
$\frac{1}{R_{eq}}=\frac{1}{R}+\frac{1}{R}=\frac{2}{R}$
which means:
$R_{eq}=\frac{R}{2}$
And calling I the current in the circuit, the voltage is given by Ohm's law:
$V=IR_{eq}=\frac{IR}{2}$

In the second situation, the resistance of each resistor is doubled: R'=2R. So, the equivalent resistance in this case is given by
$\frac{1}{R_{eq}}=\frac{1}{2R}+\frac{1}{2R}=\frac{2}{2R}=\frac{1}{R}$
which means
$R_{eq}=R$
And the new voltage is given by:
$V'=IR_{eq}=IR=2V$
which is twice the original voltage, so the voltage has doubled.

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2 years ago

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