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2 years ago

What does the constant bombardment of gas molecules against the inside walls of a container produce?

1 answer:

4 0

The constant bombardment of gas molecules against the inside walls of a container produces Pressure.

Explanation:
Pressure is defined as Force per unit Area.

P = F / A

In case of gases, the gas molecules have high Kinetic Energy and they move with high velocity. This cause them to strike against the inside wall of the container. Pressure is directly proportional to temperature. Increase in temperature cause to increase the Kinetic Energy of molecules, Hence, the rate of collisions increases resulting in increasing the pressure.

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Write the word and balanced chemical equations for the reaction between:

nadezda [96]

Answer:

3 HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

Explanation:

An acid reacts with a base producing water and a salt. Having this in mind the reaction of nitric acid (HNO₃) and Iron (III) hydroxide (Fe(OH)₃) is:

HNO₃ + Fe(OH)₃ → H₂O + Fe(NO₃)₃

The H⁺ of the acid reacts with the OH⁻ to produce H₂O. The other ions (Fe³⁺ and NO₃⁻) produce the salt

There are 3 nitrates in products. To balance the nitrates:

And this is the balanced reaction

3 0

2 years ago

What Chemicals including in Cosmetic?

Roman55 [17]

The chemicals including in cosmetic are:-

1.Talcum Powder

2.Nanoparticles

3.Coal Tar

4.Triclosan

5.Toluene

Hope this helps you.

7 0

2 years ago

Nonliving things have cells. True False

Whitepunk [10]

The answer is false.

3 0

3 years ago

Read 2 more answers

Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

3 0

2 years ago

How do the mass and height of an object affect the gravitational potential energy?

marin [14]

Answer:

B. mass and height have the same effect on gravitational potential energy.

Explanation:

Both mass and height have the same effect on the gravitational potential energy of body.

Gravitational potential energy is the energy of a body due to that of another body. It usually the energy at rest in a body.

It is mathematically expressed as;

G.P.E = m x g x h

m is the mass

g is the acceleration due to gravity

h is the height

We see that both the height and mass are directly proportional to the gravitational potential energy and as such, they have the same effect.

5 0

2 years ago