Ask question

Ask question

All categories

3 years ago

10

Write short note on

2 answers:

irakobra [83]3 years ago

8 0

Answer:

Steam distillation is a separation process which purifies isolate temperature-sensitive materials, such as natural aromatic compounds. In steam distillation, dry steam is passed through the plant material. These vapours undergo condensation and collection in receivers.

distillation under pressure is used for the purification of those substance which get decompose on their boiling point. so , a suction pump (vaccum) is fitted with a beaker in order to lower it's pressure, due to which boiling pressure decreases. so that it can be distilled of before reaching to its boiling point.

Fractional distillation is a type of distillation which involves the separation of miscible liquids. The process involves repeated distillations and condensations and the mixture is usually separated into component parts. The separation happens when the mixture is heated at a certain temperature where fractions of the mixture start to vaporize.

Explanation:

HOPE IT HELPS YOU

WITCHER [35]3 years ago

4 0

I hope it helps you ❤️❤️❤️❤️

You might be interested in

This is very difficult

Oliga [24]

Answer: C

Explanation:

6 0

3 years ago

Why water can't be burn

mojhsa [17]

Answer:because it isnt flammable

Explanation:water can not be burned

3 0

3 years ago

Determine the mass in 3.57 mol Al.

Alborosie

Answer:

b

Explanation:

8 0

2 years ago

Read 2 more answers

The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 68 minutes. Suppose

viva [34]

Answer:

The concentration would be; 0.0038 μgmL

Explanation:

Half life, t1/2 = 68 minutes

Initial Conc. [A]o = 0.12/μgmL

Final Conc [A] = ?

Time. k = 340 minutes

ln[A] = ln[A]o - kt

t1/2 = ln2 / k

k = 0.693 / t1/2 = 0.693 / 68 = 0.01019

ln[A] = ln (0.12) - 0.01019 (340)

ln[A] = -2.1203 -3.4646

ln[A] = -5.5849

[A] = 0.00375 ≈ 0.0038 μgmL

3 0

3 years ago

If a radioactive isotope has a half-life of 26.5 days, how many days does it take for a sample of the isotope to decrease by 35.

dangina [55]

Answer:

16.5 days

Explanation:

Given that:

Half life = 26.5 days

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{26.5}\ days^{-1}$

The rate constant, k = 0.02616 days⁻¹

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

35.0 % is decomposed which means that 0.35 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 1 - 0.35 = 0.65

t = 7.8 min

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.65=e^{-0.02616\times t}$

<u>t = 16.5 days.</u>

7 0

3 years ago