Answer:
0.500 M
Explanation:
The balanced equation for the neutralization reaction is as follows
NaOH + HCl —> NaCl + H2O
Molar ratio of NaOH to HCl is 1:1
Number of moles of NaOH reacted is equal to the number of HCl moles
We can use the following equation
c1v1 = c2v2
Where c1 is concentration and v1 is volume of HCl
c2 is concentration and v2 is volume of NaOH
Substituting the values
1.00 M x 10.0 mL = c2 x 20.0 mL
c2 = 0.500 M
Concentration of NaOH is 0.500 M
Answer:
161 mL
Explanation:
- Pb(NO₃)₂(aq) + Ba(OH)₂(aq) → Pb(OH)₂(s) + Ba(NO₃)₂(aq)
First we <u>calculate how many Pb⁺² moles reacted</u>, using the<em> given concentration and volume of the Pb(NO₃)₂ solution</em>:
- 163 mL * 0.656 M = 107 mmol Pb(NO₃)₂
As<em> 1 millimol of Pb(NO₃)₂ would react with 1 millimol of Ba(OH)₂,</em> to precipitate 107 mmoles of Pb(NO₃)₂ we would require 107 mmoles of Ba(OH)₂.
Using the number of moles and the concentration we can <u>calculate the required number of milliliters</u>:
- 0.666 M = 107 mmol / x mL
If two plus two is four then four plus four is two
Answer:
See below.
Explanation:
It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's.
Best Regards!
Answer:
6
Explanation:
The maximum number of electrons in the orbitals of sub-levels are given as:
for s-sublevel we have two electrons and one orbital
p-sublevel we have six electrons and three orbitals
d-sublevel we have ten electrons and five orbitals
f- sublevel we have fourteen electrons and seven orbitals
The second energy level is represented by the p-sub-level and it will accommodate 6 electrons.
