Please help i will give brainliest

Vlad1618 [11]

Answer:

J

Explanation:

Chlorine Gas is Cl2 so if it isnt on the left as that its wrong.

Then on the products see that Fe III means Fe is +3 charge so we have to have 3 Cl to balance it to 0 since each cl as -1 charge.

FInally check if the equation is balanced J is maybe H but its to blurry to tell

3 0

3 years ago

What do you think the saying ‘think globally, act locally’ means? How does this apply to the issue of plastic debris in the ocea

Tatiana [17]

I believe it means to worry about the entire planet but you should also help around your community. It applies the oceans having plastic in them because you can’t get all of the plastic out but you can pick trash around your city

8 0

3 years ago

As the speed increases how does the potential kinetic and total energy levels change

Dafna1 [17]

Hello,

As the speed increases the Energy does not change. This is because of Law of conservation of mass. Energy can be created or destroyed.

Thus the energy levels will stay the same but the form in which the energy is presented may change.

Hope this helps! Have a great day.

7 0

3 years ago

While doing a lab a student found the density of a piece of pure aluminum to be 2.85 g/cm3 the accepted value for the density of

____ [38]

Answer:

THE PERCENT ERROR IS 5.55 %

Explanation:

To calculate the percent error, we use the formula:

Percent error = Found value - accepted value / accepted value * 100

Found value = 2.85 g/cm3

Accepted value = 2.70 g/cm3

Solving for the percent error, we have:

Percent error = 2.85 g/cm3 - 2.70 g/cm3 / 2.70 g/cm3 * 100

Percent error = 0.15 / 2.70 * 100

Percent error = 0.05555 * 100

Percent error = 5.55 %

In conclusion, the percent error is 5.55 %

3 0

4 years ago

how many ml of 0.032 molar kmno4 are required to react with 50.0 ml of 0.100 molar h2c2o4 in the presence of excess h2so4

BartSMP [9]

Answer:

62.5 ml of 0.032 M KMnO₄ are required to react with 50.0 ml of 0.100 molar H₂C₂O₄ in the presence of excess H₂SO₄

Explanation:

The balanced reaction is:

2 KMnO₄ + 5 H₂C₂O₄ + 3 H₂SO₄ → K₂SO₄ + 2 MnSO₄ + 8 H₂O + 10 CO₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

KMnO₄: 2 moles
H₂C₂O₄: 5 moles
H₂SO₄: 3 moles
K₂SO₄: 1 mole
MnSO₄: 2 moles
H₂O: 8 moles
CO₂: 10 moles

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$

In this case, 50 mL (0.05 L) of 0.1 M H₂C₂O₄ react. So, replacing the data in the definition of molarity:

$0.1 M=\frac{number of moles of solute}{0.05 L}$

Solving:

number of moles of solute= 0.1 M*0.05 L

number of moles of solute= 0.005 moles

So, 0.005 moles of H₂C₂O₄ react. Then you can apply the following rule of three: if by stoichiometry 5 moles of H₂C₂O₄ react with 2 moles of KMnO₄, 0.005 moles of H₂C₂O₄ react with how many moles of KMnO₄?

$moles of KMnO_{4} =\frac{0.005moles of H_{2} C_{2} O_{4}* 2moles of KMnO_{4} }{5moles of H_{2} C_{2} O_{4} }$

moles of KMnO₄= 0.002 moles

Knowing that the molarity of KMnO₄ is 0.032 M, replacing in its definition and solving:

$0.032 M=\frac{0.002 moles}{volume}$

$volume=\frac{0.002 moles}{0.032 M}$

volume= 0.0625 L= 62.5 mL

<u><em>62.5 ml of 0.032 M KMnO₄ are required to react with 50.0 ml of 0.100 molar H₂C₂O₄ in the presence of excess H₂SO₄</em></u>

6 0

3 years ago