A helium–neon laser emits a beam of circular cross section with a radius r and a power P.?. (a) Find the maximum electric field
1 answer:
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Answer:
(a) 181.05 m/s²
(b) 13.2°
Explanation:
Given:
Radius of the circle (R) = 0.610 m
Angular acceleration (α) = 67.6 rad/s²
Angular speed (ω) = 17.0 rad/s
(a)
Radial acceleration of the ball is given as:
Plug in the given values and solve for . This gives,
Now, tangential acceleration is given by the formula:
Plug in the given values and solve for . This gives,
Now, the magnitude of total acceleration is given as the square root of the sum of the squares of tangential and centripetal accelerations. Therefore,
Plug in the given values and solve for total acceleration, . This gives,
Therefore, the magnitude of total acceleration is 181.05 m/s².
(b)
Angle of total acceleration relative to radial direction is given by the formula:
Therefore, the total acceleration makes an angle of 13.2° relative to radial direction.
Answer: : carbon tetrabromide
Explanation:
is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.
The naming of covalent compound is given by:
1. The less electronegative element is written first.
2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.
Hence, the correct name for is carbon tetrabromide.