Answer:
The tension in the rope is 20 N
Solution:
As per the question:
Mass of the object, M = 2 kg
Density of water, 
Density of the object, 
Acceleration due to gravity, g = 
Now,
From the fig.1:
'N' represents the Bouyant force and T represents tension in the rope.
Suppose, the volume of the block be V:
V = 
(1)
Also, we know that Bouyant force is given by:
Using eqn (1):
From the fig.1:
N = Mg + T
40 = 2(10) + T
T = 40 - 20 = 20 N
(B) The balloon will rise because the upward buoyant force is greater than its weight.
Explanation:
In order to evaluate what happens to the balloon, we need to compare the magnitude of the two forces acting on the balloon:
- Its weight, W, acting downward
- The buoyant force, B, acting upward
The weight of the balloon is given by:
where
m = 2.0 kg is the mass of the balloon
is the acceleration of gravity
Substituting,
The buoyant force on the balloon is given by:
where
is the air density
is the balloon's volume
is the acceleration of gravity
Substituting,
We observe that the buoyant force B is larger than the weight, so the balloon will accelerate upward, and the correct answer is
(B) The balloon will rise because the upward buoyant force is greater than its weight.
#LearnwithBrainly
I think that the girl has greater tangential acceleration because she is closer to the center and the acceleration is greater there.
Answer:
Torque = 50N x 0.3m = 15Nm
Explanation:
Torque = Force x length of lever arm. To obtain the torque simply multiply the two given values.
Answer:
I = 113.014 kg.m^2
m = 2075.56 kg
wf = 3.942 rad/s
Explanation:
Given:
- The constant Force applied F = 300 N
- The radius of the wheel r = 0.33 m
- The angular acceleration α = 0.876 rad / s^2
Find:
(a) What is the moment of inertia of the wheel (in kg · m2)?
(b) What is the mass (in kg) of the wheel?
(c) The wheel starts from rest and the tangential force remains constant over a time period of t= 4.50 s. What is the angular speed (in rad/s) of the wheel at the end of this time period?
Solution:
- We will apply Newton's second law for the rotational motion of the disc given by:
F*r = I*α
Where, I: The moment of inertia of the cylindrical wheel.
I = F*r / α
I = 300*0.33 / 0.876
I = 113.014 kg.m^2
- Assuming the cylindrical wheel as cylindrical disc with moment inertia given as:
I = 0.5*m*r^2
m = 2*I / r^2
Where, m is the mass of the wheel in kg.
m = 2*113.014 / 0.33^2
m = 2075.56 kg
- The initial angular velocity wi = 0, after time t sec the final angular speed wf can be determined by rotational kinematics equation 1:
wf = wi + α*t
wf = 0 + 0.876*(4.5)
wf = 3.942 rad/s
