1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
storchak [24]
3 years ago
11

A 1500 kg car is parked at the top of a hill 5.2 m high. At the bottom of the hill, what is the kinetic energy, in Joules, of th

e car?
Physics
1 answer:
irga5000 [103]3 years ago
4 0

Answer:

10.1

Explanation:

I think it's right?

You might be interested in
A car speeds up from 0 m/s to 14.0 m/s in 325 s. What is the acceleration?
Anton [14]

Answer: 0.04308 m/s^2

Explanation: Plug the variables into the equation: a=\frac{v-v_{0} }{t} | v equals initial speed, v_{0} equals final speed and t equals time.

8 0
3 years ago
A laser beam of wavelength λ=632.8 nm shines at normal incidence on the reflective side of a compact disc. The tracks of tiny pi
Juliette [100K]

To solve this problem we will apply the concepts given by the principles of superposition, specifically those described by Bragg's law in constructive interference.

Mathematically this relationship is given as

dsin\theta = n\lambda

Where,

d = Distance between slits

\lambda = Wavelength

n = Any integer which represent the number of repetition of the spectrum

\theta = sin^{-1} (\frac{n\lambda}{d})

Calculating the value for n, we have

n = 1

\theta_1 = sin^{-1} (\frac{\lambda}{d})\\\theta_1 = sin^{-1} (\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_1 = 23.3\°

n=2

\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (2\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = 52.28\°

n =3

\theta_2 = sin^{-1} (\frac{2\lambda}{d})\\\theta_2 = sin^{-1} (3\frac{632.8*10^{-9}}{1.6*10^{-6}})\\\theta_2 = \text{not possible}

Therefore the intensity of light be maximum for angles 23.3° and 52.28°

7 0
3 years ago
A transformer has a 240 V primary and a 60 V secondary. With a 5 ohm load connected, what is the primary current?
musickatia [10]

Answer:primary current is 3A

Explanation:

primary voltage Vp=240V

secondary voltage Vs=60V

resistance 5Ω

primary current in the circuit is

I_{P} =I_{S} \frac{V_{S}}{V_{P}}\\I_{P} =\frac{V_{S}}{R}  \frac{V_{S}}{V_{P}}\\I_{P}=\frac{60\times 60}{5\times 240\\}\\I_{P}=3 A

4 0
3 years ago
A hydrometer is made of a tube of diameter 2.3cm.The mass of the tube and it's content is 80g. If it floats in a liquid density
iris [78.8K]

Answer:

The depth to which the hydrometer sinks is approximately 24.07 cm

Explanation:

The given parameters are;

The diameter of the hydrometer tube, d = 2.3 cm

The mass of the content of the tube, m = 80 g

The density of the liquid in which the tube floats, ρ = 800 kg/m³

By Archimedes' principle, the up thrust (buoyancy) force acting on the hydrometer = The weight of the displaced liquid

When the hydrometer floats, the up-thrust is equal to the weight of the hydrometer which by Archimedes' principle, is equal to the weight of the volume of the liquid displaced by the hydrometer

Therefore;

The weight of the liquid displaced = The weight of the hydrometer, W = m·g

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ W = 80 g × g

The volume of the liquid that has a mass of 80 g (0.08 kg), V = m/ρ

V = 0.08 kg/(800 kg/m³) = 0.0001 m³ = 0.0001 m³ × 1 × 10⁶ cm³/m³ = 100 cm³

The volume of the liquid displaced = 100 cm³ = The volume of the hydrometer submerged, V_h

V_h = A × h

Where;

A = The cross-sectional area of the tube = π·d²/4

h = The depth to which the hydrometer sinks

h = V_h/A

∴ h = 100 cm³/( π × 2.3²/4 cm²) ≈ 24.07 cm

The depth to which the tube sinks, h ≈ 24.07 cm.

3 0
2 years ago
In case of collision of objects in two dimensions which statement is true after the collision?
Grace [21]

The correct answer to the question is : C) The horizontal momentum and the vertical momentum are both conserved. 

EXPLANATION :

Before coming into any conclusion, first we have to understand the law of conservation of momentum.

As per the law of conservation of momentum, the total linear as well as angular momentum of an isolated system is always conserved . The law of conservation of energy is a universal fact.

Hence, during any type of collision, the total momentum is always conserved.

Hence, the total horizontal momentum as well as total vertical momentum are always conserved during both elastic as well as inelastic collision.



5 0
3 years ago
Read 2 more answers
Other questions:
  • Rachel has been reading her physics book. She takes her weighing scales into an elevator and stands on them. If her normal weigh
    5·1 answer
  • Identify the normal force on the shopping cart after 75 newtons of groceries are added to the cart
    5·2 answers
  • Find the power required to give a brick 60 j of potential energy in a time of 3.0 s .
    8·1 answer
  • It's most critical that you'll be critical of Howard Gardner's seven intelligences if you
    14·1 answer
  • A nylon thread is subjected to a 8.5-N tension force. Knowing that E 5 3.3 GPa and that the length of the thread increases by 1.
    9·1 answer
  • Which process represents a chemical change
    9·2 answers
  • When the distance between an object and a flat mirror is 5 m, the distance between the image and the mirror is a. 5 m.
    12·1 answer
  • Plz help i dont understand
    11·1 answer
  • What landforms are found on the Moon? (Select all that apply.)
    13·1 answer
  • (fill in the blank) , itself a silver shape beneath the steadfast constellations, simon's dead body moved out toward the open se
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!