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3 years ago

An alpha particle is made up of

Chemistry

1 answer:

Ipatiy [6.2K]3 years ago

6 0

Answer:

Two protons and two neutrons

Explanation:

The nucleus of the helium atom

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What are conclusions based on?

kati45 [8]

They're based on the results of your testing.

7 0

3 years ago

Read 2 more answers

Using the following standard reduction potentials, Fe3+(aq) + e- → Fe2+(aq) E° = +0.77 V Ni2+(aq) + 2 e- → Ni(s) E° = -0.23 V ca

lina2011 [118]

<u>Answer:</u> The above reaction is non-spontaneous.

<u>Explanation:</u>

For the given chemical reaction:

$Ni^{2+}(aq.)+2Fe^{2+}(aq.)\rightarrow 2Fe^{3+}(aq.)+Ni(s)$

Here, nickel is getting reduced because it is gaining electrons and iron is getting oxidized because it is loosing electrons.

We know that:

$E^o_{(Fe^{3+}/Fe^{2+})}=0.77V\\E^o_{(Ni^{2+}/Ni)}=-0.23V$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=-0.23-0.77=-1.0V$

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$

As, the standard electrode potential of the cell is coming out to be negative for the above cell. Thus, the standard Gibbs free energy change of the reaction will become positive making the reaction non-spontaneous.

Hence, the above reaction is non-spontaneous.

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3 years ago

A 6 kg rock is sitting at the edge of a 100 m tall cliff. What is the potential energy of the rock with respect to the ground?

Hatshy [7]

Potential energy can be calculated by the formula Pe=mgh. Plug in your values:

Pe=mgh
Pe=(6 kg)(9.8m/s^2)(100 m)
Pe=5880 kg x m^2/s^2, or 5880 Joules

5 0

3 years ago

Object A has a mass of 3,600 kilograms. Object B has a mass of 600 kilograms. The weight of Object B will be ________ times the

Natalija [7]

Hi the answer is 1/6, because 1/6 of 3,600 is 600, so it's 1/6. Have a great day!

7 0

4 years ago

(01.07 но) An experiment was conducted to determine the density of a liquid. The table shows a partial record of the experiment

Anestetic [448]

Answer:

How do you find the density of a liquid experiment?

To measure the density of a liquid you do the same thing you would for a solid. Mass the fluid, find its volume, and divide mass by volume. To mass the fluid, weigh it in a container, pour it out, weigh the empty container, and subtract the mass of the empty container from the full container.

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3 years ago