Answer:
8.24 m/s
Explanation:
Given:
t = 2.10 s
v₀ᵧ = 0 m/s
vₓ = 22.2 cos(-68.2) m/s
aₓ = 0 m/s²
Find: v₀
In the x direction:
v = at + v₀
22.2 cos(-68.2) = (0) (2.10) + v₀ₓ
v₀ₓ = 8.24
v₀² = v₀ₓ² + v₀ᵧ²
v₀² = (8.24)² + (0)²
v₀ = 8.24 m/s
The frictional force between two surfaces is given by:

where

is the coefficienct of friction

is the force with which one surface is pushed against the other one
Looking at the formula, we see that there are two possible ways to increase the friction:
1) by increasing the coefficient of friction

(for instance, by making the surfaces more "rough"
2) by increasing

, the force with which one surface is pushed against the other
Similarly, in order to decrease the friction, the two possible ways are:
1) by reducing the coefficient of friction
2) by reducing the force
Momentum is the product of mass and velocity of a body. In this case, the bus has a mass of 18200 kg and moving with a velocity of 10 m/s.
Therefore, the momentum of the bus will be, 18200×10 = 182,000 kgm/s.
Thus a ball of mass 0.142 kg will require to travel with a speed of;
= 182000/0.142
= 1.282 ×10∧6 m/s to have the same momentum with the bus.
Answer:
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