Answer:
0.8214 m/s^2
Explanation:
Fnet= Fpushed - Ffriction
Fpushed = 12.7N Ffriction = 8.33N
Fnet = 12.7N - 8.33N = 4.37N
Fnet= mass(acceleration)
Fnet = 4.37N mass = 5.32 kg
4.37N = 5.32 kg(acceleration)
acceleration= 0.8214 m/s^2
It was decrease because the water js going from one place to another
Answer:
9.2 V
Explanation:
The RMS value of an AC is the effective value of a varying voltage or current in DC, that is the equivalent value of the AC which produces the same effect as an DC. For example if a motor is supplied by a 9V RMS voltage, it will rotate as if the voltage applied was 9V DC.
The RMS value is given by:
RMS voltage = Peak voltage * 1/√2
Given that the maximum voltage should not exceed 13 V, this means that the peak voltage is 13 V. The maximum RMS voltage is:
RMS voltage = Peak voltage * 1/√2 = 13 * 1/√2 = 9.2 V
Answer:
Her speed at the bottom of the slope is 25.665 m/s
Explanation:
Here we have
Initial velocity, v₁= 15 m/s
Final velocity = v₂
The energy balance present in the system can be represented as
![\frac{1}{2}mv_2^2 -\frac{1}{2}mv_1^2 - mgh = W](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv_2%5E2%20-%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2%20-%20mgh%20%3D%20W)
Where:
m = Mass of the cyclist = 70 kg
W = work done by the drag force = ![-F_Dd](https://tex.z-dn.net/?f=-F_Dd)
Where:
d = Distance traveled = 450 m
Therefore,
and
![v_2^2 =\frac{ \frac{1}{2}mv_1^2 + mgh -F_Dd}{ \frac{1}{2}m} = v_1^2 + 2gh -\frac{ 2F_Dd}{ m} = 15^2 + 2\times 9.8\times 30 - \frac{2\times 12\times 450}{70}](https://tex.z-dn.net/?f=v_2%5E2%20%3D%5Cfrac%7B%20%5Cfrac%7B1%7D%7B2%7Dmv_1%5E2%20%2B%20mgh%20%20-F_Dd%7D%7B%20%5Cfrac%7B1%7D%7B2%7Dm%7D%20%20%3D%20v_1%5E2%20%2B%202gh%20-%5Cfrac%7B%20%20%202F_Dd%7D%7B%20m%7D%20%3D%2015%5E2%20%2B%202%5Ctimes%209.8%5Ctimes%2030%20-%20%5Cfrac%7B2%5Ctimes%2012%5Ctimes%20450%7D%7B70%7D)
= 658.714 m²/s²
v₂ = 25.665 m/s
Her speed at the bottom of the slope = 25.665 m/s.
sound energy hope this helps please give brainliest