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stepladder [879]
3 years ago
9

The ears are ____ and ____ to the shoulders and ____ to the nose.

Physics
2 answers:
Levart [38]3 years ago
3 0
The ears are superior and posterior to the shoulders and lateral to the nose.
LiRa [457]3 years ago
3 0

Which describes a relationship based on the general theory of relativity?

Acceleration in space and magnetism on Earth have opposite effects on objects.Acceleration in space and magnetism on Earth have the same effects on objects.Acceleration in space and gravity on Earth have opposite effects on objects.<span>Acceleration in space and gravity on Earth have the same effects on objects. </span>
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Breanna is standing beside a merry-go-round pushing 19° from the tangential direction and is able to accelerate the ride and her
leva [86]

To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.

Torque in a body is defined as,

\tau_l = F*d

And in angular movement like

\tau_a = I*\alpha

Where,

F= Force

d= Distance

I = Inertia

\alpha = Acceleration Angular

PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.

\tau= F*cos(19)*d

On the other hand we have the speed data expressed in RPM, as well

\omega_f = 10rpm = 10\frac{1rev}{1min}(\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega_f = 1.0471rad/s

Acceleration can be calculated by

\alpha = \frac{\omega_f}{t}

\alpha = \frac{1.0471}{9}

\alpha = 0.11rad/s^2

In the case of Inertia we know that it is equivalent to

I = \frac{1}{2}mr^2 = \frac{1}{2}(750)*(2.3)^2

I = 1983.75kg.m^2

Matching the two types of torque we have to,

\tau_l=\tau_a

Fd=I\alpha

Fcos(19)*2.3=1983.75(0.11)

F=100.34N

PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,

W = \frac{1}{2}I\omega_f^2

W= \frac{1}{2}(1983.75)(1.0471)^2

W=1087.51J

7 0
2 years ago
Bernoulli's principle can be used to explain the lift force on an airplane wing. How must an airplane's wing be designed to ensu
mihalych1998 [28]

Answer:

Airplane wings must be designed to ensure that air molecules move more rapidly over the top surface of the wing, creating a region of lower pressure.

Explanation:

6 0
3 years ago
Read 2 more answers
The human activities in two locations are described below:
Bogdan [553]
Air pollution level is higher in Location B, because poisonous fumes are produced when coal burns.
5 0
3 years ago
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,how do charged objects react???quiet urgent
son4ous [18]
Any charged object can<span> exert the force upon other objects ... i think tell me if im right</span>
8 0
3 years ago
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Vector A has magnitude of 15.0 m/s and is 75° counter-clockwise up from the x-axis. What are the x- and y-components of the vect
LiRa [457]

Answer:

x component 3.88 y- component 14.488

Explanation:

We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure

Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )

y- component will be 15 sin 75°=14.488

For verification the resultant of x and y component should be equal to 15

So resultant =\sqrt{14.488^2+3.88^2}=15

3 0
3 years ago
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