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3 years ago

Which of the following solutes will lower the freezing point of water the most?

Chemistry

1 answer:

Marianna [84]3 years ago

8 0

<u>Answer:</u> D. the ionic compound calcium fluoride $(CaF_2)$

The correct option here is the fourth one.

<u>Explanation:</u>

Salt like compounds addition to water is likely to be inducing certain changes in temperature of freezing into solid and also alter the temperature of boiling.

It is noticed that addition of salts in water mostly tends to get lower the freezing temperatures from the original freezing point of water and among the given 3 options calcium fluoride tends to lower the freezing point most when compared to others.

Thus as vant hoff factor is highest factor for $CaF_{2}$ and the freezing point will be lowest.

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as the temperature on a sample of gas with a constant volume increases, the pressure _____. decreases stays the same increases

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The pressure increases as temperature increases, as a gas is heated it expands, so in a confined container (constant volume) pressure must increase, this can be observed through the universal gas law (pv=nRT)

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3 years ago

Which of the following statements correctly distinguishes between an acidic and a basic solution? . A. An acidic solution contai

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3 0

3 years ago

*multiple choice*

OleMash [197]

I think the answer is A but I could be wrong

4 0

3 years ago

2-ciclopropilpropano

DaniilM [7]

Answer:

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Explanation:

3 0

3 years ago

I need help with this, please :00000

mojhsa [17]

theoretical yield of the reaction is 121.38 g of NH₃ (ammonia)

limiting reactant is N₂ (nitrogen)

excess reactant is H₂ (hydrogen)

Explanation:

We have the following chemical reaction:

N₂ + 3 H₂ → 2 NH₃

Now we calculate the number of moles of each reactant:

number of moles = mass / molar weight

number of moles of N₂ = 100 / 28 = 3.57 moles

number of moles of H₂ = 100 / 2 = 50 moles

From the chemical reaction we see that 3 moles of H₂ are reacting with 1 moles of N₂, so 50 moles of H₂ are reacting with 16.66 moles of N₂ but we only have 3.57 moles of N₂ available, so the limiting reactant will be N₂ and the excess reactant will be H₂.

Knowing the chemical reaction and the limiting reactant we devise the following reasoning:

if 1 mole of N₂ produce 2 moles of NH₃

then 3.57 moles of N₂ produce X moles of NH₃

X = (3.57 × 2) / 1 = 7.14 moles of NH₃

mass = number of moles × molar weight

mass of NH₃ = 7.14 × 17 = 121.38 g

theoretical yield of the reaction is 121.38 g of NH₃

Learn more about:

limiting reactant

brainly.com/question/13979150

#learnwithBrainly

4 0

4 years ago