What is the chemical formula for the compound ammonium phosphate?

PLEASE HURRY AND CHECK IMMAGE. Predict the shape of the molecule.

Karo-lina-s [1.5K]

Answer:

A. bent

Explanation:

5 0

2 years ago

The graph shows the consumption of gasoline and diesel fuels by vehicles in the United States for a period of 40 years.

grigory [225]

Answer:

B. It would lead to an increase of global temperatures.

Explanation:

Gas burns when it is hot. Therefore the more gas that our cars consume, the hotter the air will be when the car releases those gas vapors. Causing the air to become hotter.

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5 0

2 years ago

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The pH of a solution prepared by mixing 40.00 mL of 0.10 M NH3 with 50.00 mL of 0.10 M NH4Cl and 30mL of 0.05 M H2SO4 is 5.17. A

liq [111]

Answer:

Following are the answer to this question:

Explanation:

The value of pH solution is =5.17 So, the p^{OH}:

$p^{OH}$ =14-56.17

=8.823

The volume of the $NH_{3}$ = 40.00 ml

convert into the liter= 0.040L

The value of the concentrated $NH_{3}$ =0.10 M

The volume of the $NH_{4}Cl$ = 50.00 ml

convert into the liter= 0.050L

The value of concentrated $NH_{4}Cl$ = 0.10 M

The volume of the $H_{2}So_{4}$ = 30 ml

convert into the liter= 0.030L

The value of concentrated $H_2So_4$ =0.05 M

Calculating total volume=(0.40+0.050+0.030)

=0.120 L

calculating the new concentrated value of $NH_3$ = $\frac{0.10\times 0.040}{0.120}= 0.33 \ M$

calculating the new concentrated value of $NH_4Cl$ = $\frac{0.050\times 0.10}{0.120}= 0.04166 \ M$ calculating the new concentrated value of $H_2So_4= \frac{0.030\times 0.05}{0.120}= 0.0125 \ M$ when 1 mol $H_2So_4$ produced 2 mols $H^{+}$ so, 0.0125 in $H_2So_4$ produced:

$=4 \times (2 \times 0.0125) \ mol H^{+}\\\\= 0.025 mol H^{+}$

create the ICE table:

$NH_3 \ \ \ \ \ \ \ \ + H^{+} \ \ \ \ \ \ \longrightarrow NH_4^{+}$

I (m) 0.033(m) 0.025 0.04166

C -0.025 -0.025 + 0.025

E 8.3\times 10^{-3} 0 0.0667

now calculating pH:

when ph= 8.83:

$P^{H}= p^{kb}|+ \log\frac{[NH_4^{+}]}{[NH_3]}\\\\8.83=p^{kb}+\log\frac{0.0667}{8.3 \times 10^{-3}}\\\\p^{kb}=8.83-0.9069\\\\ \ \ \ =7.7231 \\\\\ The P^{kb} \ for \ NH_3 \ is =7.7231\\\\\ The P^{kb} \ for N^{+}H_4=14-7.7231\\\\\ \ \ \ \ \ =6.2769$

5 0

3 years ago

If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?

GarryVolchara [31]

Answer:

385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

2 H₂ + O₂ → 2 H₂O

According to Equation,

4.032 g ( 2 mol) H₂ reacts to produce = 36.03 g (2 mol) of H₂O

So,

48.6 g H₂ on reaction will produce = X g of H₂O

Solving for X,

X = (48.6 g × 36.03 g) ÷ 4.032 g

X = 434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

36.03 g (2 mol) H₂O is produced by = 31.998 g (1 mol) of O₂

So,

434.29 g of H₂O will be produced by = X g of O₂

Solving for X,

X = (434.29 g × 31.998 g) ÷ 36.03 g

X = 385.69 g of O₂

8 0

3 years ago

How do invertebrates affect the oxygen levels of compost and soil?.

Digiron [165]

Invertebrates affect the oxygen levels of compost and soil by reducing it.

<h3>How respiration works?</h3>

Cellular respiration is the process by which living organisms obtain energy by breaking down food molecules in their cells.

Every living organism undergoes the process of cellular respiration and make use of oxygen molecules in the process.

This means that invertebrates will make use of the oxygen gas present in compost and the soil for respiration, hereby reducing it.

Learn more about respiration at: brainly.com/question/480297

8 0

2 years ago