Mostly because the lake smell really bad and the waters really dirty
- The chemical symbol of the isotope boron-11 is ¹¹B.
- The atomic mass of the isotope boron-11 is equal to 11.009306.
- The abundance in nature of the isotope boron-11 is equal to 80.1%.
<h3>What is an isotope?</h3>
An isotope can be defined as the atom of a chemical element that has the same number of protons but different number of neutrons. This ultimately implies that, the isotopes of an element have the same atomic number (number of protons) but different atomic mass (number of neutrons).
In Chemistry, there are two main isotopes of boron and these include the following:
Boron-11 is the most stable isotope of boron and it is characterized by the following:
- The chemical symbol of the isotope boron-11 is ¹¹B.
- The atomic mass of the isotope boron-11 is equal to 11.009306.
- The abundance in nature of the isotope boron-11 is equal to 80.1%.
Read more on Boron-11 here: brainly.com/question/6283234
#SPJ1
The littoral zone of a lake is the area closest to the shore. It has very little biological activity but includes a lot of oxygen. The water in the lake's littoral zone is freshwater, free of living organisms such as plants and fish.
The answer is nuclear energy
Answer:
0.0303 Liters
Explanation:
Given:
Mass of the potassium hydrogen phosphate = 0.2352
Molarity of the HNO₃ Solution = 0.08892 M
Now,
From the reaction it can be observed that 1 mol of potassium hydrogen phosphate reacts with 2 mol of HNO₃
The number of moles of 0.2352 g of potassium hydrogen phosphate
= Mass / Molar mass
also,
Molar mass of potassium hydrogen phosphate
= 2 × (39.09) + 1 + 30.97 + 4 × 16 = 174.15 g / mol
Number of moles = 0.2352 / 174.15 = 0.00135 moles
thus,
The number of moles of HNO₃ required for 0.00135 moles
= 2 × 0.00135 mol of HNO₃
= 0.0027 mol of HNO₃
Now,
Molarity = Number of Moles / Volume
thus,
for 0.0027 mol of HNO₃, we have
0.08892 = 0.0027 / Volume
or
Volume = 0.0303 Liters
