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Ludmilka [50]
3 years ago
5

Arenediazoniums can undergo electrophilic aromatic substitutions with a wide variety of activated aromatic compounds to yield ne

w azo dyes.
a. True
b. False
Chemistry
1 answer:
mel-nik [20]3 years ago
4 0
B false
I did this last year and it’s false
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When a hydrogen atom covalently bonds to another atom, how many electrons associated with this hydrogen atom become involved in
STatiana [176]

Explanation:

A covalent bond is defined as the occurrence of a bond due to the sharing of electrons between the combining atoms.

Atomic number of hydrogen atom is 1 and its electronic configuration is 1s^{2}. So, in order to complete its octet it needs to gain or mutually shares one electron.

A covalent bond is generally formed between non-metal atoms.

Thus, we can conclude that hydrogen has only one electron that will be involved in the formation of a covalent bond.

8 0
3 years ago
Which of the following elements would you expect to be ductile and
aksik [14]

Answer:

ductile - germanium

mellabe - zirconium

8 0
3 years ago
What Is a combination of substances that are combined physically but not chemically
adoni [48]
It is a heterogenous mixture
7 0
3 years ago
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Predict the aldol product when the following ketone undergoes self-condensation in the presence of NaOH. Do not show the dehydra
Anit [1.1K]

Answer:

β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.

Explanation:

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5 0
3 years ago
"how many molecules of carbon dioxide exit your lungs when you exhale 5.00 × 10−2 mol of carbon dioxide, co2?"
IrinaVladis [17]
We are going to use Avogadro's constant to calculate how many molecules of

carbons dioxide exist in lungs:

when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in

CO2 when the number of moles is 5 x 10^-2

number of molecules = moles of CO2 * Avogadro's number

                                     = 5 x 10^-2  * 6.02 x 10^23

                                     = 3 x 10^22 molecules 

∴ There are 3 x 10^22 molecules in CO2 exist in lungs 
5 0
3 years ago
Read 2 more answers
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