Answer: Time required to deposit an even layer of gold with given thickness is 
sec.
Explanation:
The given data is as follows.
Surface area = 49.8 
,
Density of gold = 19.3 
,
Current = 3.15 A, thickness of gold layer = 
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
= 
= 0.05988 
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.
= sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is sec.
The earth is a vast, complex system powered by two sources of energy: an internal source (the decay of radioactive elements in the geosphere, which generates geothermal heat) and an external source (the solar radiation received from the Sun); the vast majority of the energy in the earth system comes from the Sun.
Answer:
Q = 44.9 j
Explanation:
Mass of iron = 5.0 g
Change in temperature = 20 °C
Specific heat of iron = 0.449 j/g.°C
Heat transferred = ?
Formula:
<em>Q = m.c. ΔT
</em>
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Solution:
<em>Q = m.c. ΔT
</em>
Q = 5 g × 0.449 j/g.°C × 20 °C
Q = 44.9 j
Explanation:
one mole of any substance there are 6.022×1023 units of that substance. (This number is called Avogadro's number, NA.)
We need to convert the mass of silicon to moles using the molar mass of silicon, 28.06gmol. This number means that one mole of pure silicon would have a mass of 28.06g. Our given mass, however, is in milligrams; to convert this to grams we'll use the conversion factor 1g103mg:
5.86mg Si(1g103mg)=0.00586g Si
Now, using silicon's molar mass, we'll convert this mass to moles of Si:
0.00586g Si(1mol Si28.06g Si)=2.09×10−4mol Si
Finally, let's use Avogadro's number to convert
