Answer:
The process 'Selective breeding' is used by humans to develop new organisms with desirable characteristics.
Explanation:
Answer:
Force = Mass x Acceleration
12 x 5 = 60
60 Newton’s is your final answer
<u>Answer:</u>
![\Delta E=E_{final}-E_{initial}](https://tex.z-dn.net/?f=%5CDelta%20E%3DE_%7Bfinal%7D-E_%7Binitial%7D)
![\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}](https://tex.z-dn.net/?f=%5CDelta%20E%3D-1312%5B%5Cfrac%7B1%7D%7B%28n_f%5E2%29%7D-%5Cfrac%20%7B1%7D%7B%28n_i%5E2%20%29%7D%5DKJ%20mol%5E%7B-1%7D)
![\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}](https://tex.z-dn.net/?f=%5CDelta%20E%3D-1312%5B%5Cfrac%7B1%7D%7B3%5E2%29%7D-%5Cfrac%20%7B1%7D%7B%281%5E2%20%29%7D%5DKJ%20mol%5E%7B-1%7D)
![\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}](https://tex.z-dn.net/?f=%5CDelta%20E%3D-1312%5B%5Cfrac%7B1%7D%7B%289%29%7D-%5Cfrac%20%7B1%7D%7B%281%20%29%7D%5DKJ%20mol%5E%7B-1%7D)
![\Delta E=-1312[0.111-1]KJ mol^{-1}](https://tex.z-dn.net/?f=%5CDelta%20E%3D-1312%5B0.111-1%5DKJ%20mol%5E%7B-1%7D)
![\Delta E=1166 KJ mol^{-1}](https://tex.z-dn.net/?f=%5CDelta%20E%3D1166%20KJ%20mol%5E%7B-1%7D)
![\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}](https://tex.z-dn.net/?f=%5Cfrac%7B%3D1166%2C000%20%5Cmathrm%7BJ%7D%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5Ctext%20%7B%20photons%20%7D%7D)
![=193623 \times 10^{-23} \frac {J}{photon}](https://tex.z-dn.net/?f=%3D193623%20%5Ctimes%2010%5E%7B-23%7D%20%20%5Cfrac%20%7BJ%7D%7Bphoton%7D)
![\Delta E=1.93623 \times 10^{-18} \frac {J}{photon}](https://tex.z-dn.net/?f=%5CDelta%20E%3D1.93623%20%5Ctimes%2010%5E%7B-18%7D%20%20%5Cfrac%20%7BJ%7D%7Bphoton%7D)
![\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}](https://tex.z-dn.net/?f=%5CDelta%20E%3D%5Cfrac%20%7Bh%5Ctimes%20c%7D%7B%5Clambda%7D%20%5C%5C%5C%5C%3D%5Cfrac%20%7B%286.626%5Ctimes%2010%5E%7B-34%7D%20J%20s%20%5Ctimes%203%20%5Ctimes%2010%5E8%20ms%5E%7B-1%7D%29%7D%7B%5Clambda%7D)
h is planck's constant
c is the speed of light
λ is the wavelength of light
![\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18} J/photon)}](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%20%7Bh%5Ctimes%20c%7D%7B%5CDelta%20E%7D%5C%5C%5C%5C%3D%5Cfrac%20%7B%286.626%5Ctimes10%5E%7B-34%7D%20J%20s%5Ctimes3%20%5Ctimes%2010%5E8%20ms%5E%7B-1%7D%29%7D%7B%281.93623%5Ctimes10%5E%7B-18%7D%20%20J%2Fphoton%29%7D)
Wavelength
![\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m} =103 nm (Answer)](https://tex.z-dn.net/?f=%5Clambda%20%3D10.3%20%5Ctimes%2010%5E%7B-8%7D%20m%20%5Ctimes%20%5Cfrac%20%7B%2810%5E9%20nm%29%7D%7B1m%7D%20%20%3D103%20nm%20%28Answer%29)
<em>Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is </em><u><em>103 nm.</em></u>
There are 22 pairs of <span>homologous chromosomes are found in human body cells.</span>
Answer:
3 moles of Calcium Oxide are formed
Explanation:
Based on the reaction of Calcium Ca, with oxygen, O₂, to produce calcium oxide, CaO is:
2Ca + O₂ → 2CaO
<em>where 2 moles of calcium produce 2 moles of Calcium oxide.</em>
That means, if 3 moles of Ca react in presence of oxygen:
3 moles of calcium oxide are formed