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NISA [10]
3 years ago
9

Michael loaded 84 boxes onto a truck in 12 minutes what is the unit rate​

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Answer:

7

Step-by-step explanation:

84/12= 7

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How to find 4x=14y and if it is parallel, perpendicular or neither to -2x+7y=14
RUDIKE [14]
4x = 14y
y = 4/14(x)
y = 2/7(x) slope = 2/7

<span>-2x+7y=14
7y = 2x + 14
  y = 2/7(x) + 2 slope = 2/7

parallel lines, slope is the same
both lines have slopes equal 2/7

answer
</span><span>parallel</span>
7 0
3 years ago
1Jada made 6 cups of blueberry jam and divided the jam equally among 4 containers. How much jam went in each container? ​I pick
creativ13 [48]

Answer:

That would be 1.5

Step-by-step explanation:

Here it is.

3 0
3 years ago
Which is 625 written as a power of 5 (exponets) A. 4*5 B.3*5 C.5*3 D.5*4
OleMash [197]
<span>625 written as a power of 5 = 5^4
because
5^4 = (5) * (5) *(5) * (5)  =625

answer is
</span><span>D.5^4</span>
8 0
3 years ago
Read 2 more answers
Do this problem for me? 1st correct answer gets a brainliest...
Fantom [35]

The expression x > -4 means "all the numbers stricktly greater than -4"

Since the number line is oriented with positive direction going to the right, a number is greater than another if its sits to its right.

So, we want all the numbers to the right of -4, excluded -4 itself.

So, the answer is D.

7 0
3 years ago
An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

4 0
3 years ago
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