Answer: 12033 kJ of heat produced per kg of
formed during the combustion of benzene
Explanation:
The balanced chemical equation for combustion of benzene is :
= -6278 kJ
Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and
for the reaction comes out to be negative.
(1kg=1000g)
According to stoichiometry :
12 moles of
on combustion produce heat = 6278 kJ
Thus 23 mole of
on combustion produce heat =![\frac{6278}{12}\times 23=12033kJ](https://tex.z-dn.net/?f=%5Cfrac%7B6278%7D%7B12%7D%5Ctimes%2023%3D12033kJ)
Thus 12033 kJ of heat produced per kg of
formed during the combustion of benzene
Answer:
The speed of sound in hydrogen gas is 361.5 ![^{\circ} C](https://tex.z-dn.net/?f=%5E%7B%5Ccirc%7D%20C)
Explanation:
It is given that the temperature is 50
.
The speed of sound in meter per second is calculated by an equation.
The equation states that speed of the sound in meter per second is equal to the sum of the product of the temperature in degree celsius with 0.60 and a constant that is 331.5.
The equation is written as:
![speed \ of \ sound \left(m/s \right) = 0.60 \times T + 331.5](https://tex.z-dn.net/?f=speed%20%5C%20of%20%5C%20sound%20%5Cleft%28m%2Fs%20%5Cright%29%20%3D%200.60%20%5Ctimes%20T%20%2B%20331.5)
Put the value of T = 50 then the equation becomes,
![speed \ of \ sound \left(m/s \right) = 0.60 \times 50 + 331.5](https://tex.z-dn.net/?f=speed%20%5C%20of%20%5C%20sound%20%5Cleft%28m%2Fs%20%5Cright%29%20%3D%200.60%20%5Ctimes%2050%20%2B%20331.5)
Speed of sound (in m/s) = 361.5 m/s
Answer:
The rate at which sulfur dioxide is being produced is 0.90 kg/s.
Explanation:
Volume of oxygen gas consumed in second ,V= 994 L
Pressure of the gas = p
Temperature of the gas = T = 170°C= 170 + 273 K=443 K
Moles of oxygen gas consumed in a second = n
( ideapl gas equation)
![n=\frac{PV}{RT}=\frac{0.77 atm\times 994 L}{0.0821 atm L/mol K\times 443 K}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D%3D%5Cfrac%7B0.77%20atm%5Ctimes%20994%20L%7D%7B0.0821%20atm%20L%2Fmol%20K%5Ctimes%20443%20K%7D)
n = 21.044 mole
Moles of dioxygen gas consumed per second = 21.044 mol
(Claus process)
According to reaction, 3 moles of dioxygen gives 2 moles of sulfur dioxide gas.Then 21.044 moles of dioxygen will give;
of sulfur dioxide
Mass of 14.029 moles of sulfur dioxide gas;
14.029 mol × 64 g/mol = 897.86 g
897.86 g = 0.89786 kg ≈ 0.90 kg
Mass of sulfur dioxide produced per second = 0.90 kg
The rate at which sulfur dioxide is being produced is 0.90 kg/s.
Answer:
C. democritusm John dalton, JJ Thomason, Ernest Rutherford, Neils Bohr, and Erwin Schrodinger.