Sir James Chadwick was the scientist who discovered the neutron. The electron and proton had already been found but with the neutron known, we knew everything that made up our universe. He won the 1935 Nobel Peace Prize for his discovery.
The answer is 11.0231131%, i hope this helped if it did please help me.
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Answer:
opg
Explanation:
A series of chemical reactions transform Volatile Organic Compounds (VOCs) into substances that combine with nitrogen dioxide to produce PAN (Peroxyacytyl nitrate), yet another element in smog. Nitrogen dioxide in the air also reacts with water vapor to form nitric acid, one of the types of acid in acid rain.
Answer:
The correct answer should be 12.72 pH of the mixed solution and 9.94g mass of solid BASO4 formed.
Explanation:
The molecules of Ba(OH)2 are : 1.00M x 0.05L = 0.05 ( moles )
The molecules of H2SO4 are : 0.494M x 0.0864L = 0.0426816
Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O
0.0426816<--- 0.0426816
The mixed solution is Ba(OH)2 with 0.05 - 0.0426816 = 0.0073184
The concentration of mixed solution is : 0.0073184 : ( 0.05 + 0.0864 ) = 0.054 M
The pH of mixed solution is 14 - -log[0.054] = 14 - 1.27 = 12.73 PH
And the mass of BaSO4 is 0.0426816 x ( 137 + 32 + 16 x 4 ) = 9.94 gams.
Answer:
Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.
Explanation:
In the reaction 
, we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.
The chemical equation can then be rewritten as 
, which, if looking at the individual charges of Li and Cl in lithium chloride, becomes 
. Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.
Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of 
, where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, 
, and become the 
ion. Similarly, Cl has an electron configuration of 
(or ![[Ne]3s^{2}3p^{5}](https://tex.z-dn.net/?f=%5BNe%5D3s%5E%7B2%7D3p%5E%7B5%7D)
), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration ![[Ne]3s^{2}3p^{6}](https://tex.z-dn.net/?f=%5BNe%5D3s%5E%7B2%7D3p%5E%7B6%7D)
(or ![[Ar]](https://tex.z-dn.net/?f=%5BAr%5D)
) in order to have an electron configuration where the n = 3 electron shell is full, 
, and become the 
ion. Thus, when Li and Cl bond, Li will lose the electron ![[1, 0, 0, +\frac{1}{2}]](https://tex.z-dn.net/?f=%5B1%2C%200%2C%200%2C%20%2B%5Cfrac%7B1%7D%7B2%7D%5D)
and transfer it to Cl, where it will become the electron ![[3, 1, 1, -\frac{1}{2}]](https://tex.z-dn.net/?f=%5B3%2C%201%2C%201%2C%20-%5Cfrac%7B1%7D%7B2%7D%5D)
, thus conserving charge, as there is an equal total number of electrons before and after the reaction.
