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mamaluj [8]
3 years ago
9

HNO3 is an Arrhenius ______________ and increases the concentration of __________ when added to water.

Chemistry
1 answer:
creativ13 [48]3 years ago
7 0
1. Acid , H+ ion
2. Base , OH- ion
3. Base , OH- ion
4. Acid , H+ ion
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Which of the following is the most accurate description of all known spaces
vazorg [7]

Answer:

where are the following??

like anything? any animal?

Explanation:

7 0
3 years ago
classify the following compounds as ionic (metal + nonmetal) , covalent (nonmetal + nonmetal) or both (compound containing a pol
musickatia [10]

Answer:

1. ionic

2. covalent

3. covalent

4. both

Explanation:

6 0
3 years ago
Given K = 3.61 at 45°C for the reaction A(g) + B(g) equilibrium reaction arrow C(g) and K = 7.19 at 45°C for the reaction 2 A(g)
Firlakuza [10]

Answer:

K = 0.55

Kp = 0.55

mol fraction B = 0.27

Explanation:

We need to calculate the equilibrium constant for the reaction:

C(g) + D(g) ⇄ 2B(g)              K₁= ?                       (1)

and we are given the following equilibria with their respective Ks

A(g) + B(g) ⇄ C(g)                 K₂= 3.61                 (2)

2 A(g) + D(g)  ⇄ C(g)             K₃= 7.19                 (3)

all at 45 ºC.

What we need to do to solve this question is to manipulate equations (2) and (3)  algebraically  to get our desired equilibrium (1).

We are allowed to reverse  reactions, in that case we take the reciprocal of K as our new K' ; we can also  add two equilibria together, and the new equilibrium constant will be the product of their respective Ks .

Finally if we multiply by a number then we raise the old constant to that factor to get the new equilibrium constant.

With all this  in mind, lets try to solve our question.

Notice A is not in our goal equilibrium (3)  and we want D as a reactant . That  suggests we should reverse the first equilibria and multiply it by two since we have 2 moles of B  as product in our  equilibrium (1) . Finally we would add (2) and (3) to get  (1) which is our final  goal.

2C(g)             ⇄  2A(g) + 2B(g)  K₂´= ( 1/ 3.61 )²  

                                   ₊

2 A(g) + D(g)  ⇄     C(g)               K₃ = 7.19  

<u>                                                                                    </u>

C(g) + D(g)     ⇄    2B(g)       K₁ = ( 1/ 3.61 )²   x  7.19

                                             K₁ = 0.55

Kp is the same as K = 0.55 since the equilibrium constant expression only involves  gases.

To compute the last part lets setup the following mnemonic  ICE table to determine the quantities at equilibrium:

pressure (atm)        C             D           B

initial                     1.64          1.64         0

change                    -x             -x        +2x

equilibrium          1.64-x         1.64-       2x

Thus since

Kp =0.55 = pB²/ (pC x pD) = (2x)²/ (1.64 -x)²  where p= partial pressure

Taking square root to both sides of the equation we have

√0.55 = 2x/(1.64 - x)

solving for x  we obtain a value of 0.44 atm.

Thus at equilibrium we have:

(1.64 - 0.44) atm = 1.20 atm = pC = p D

2(0.44) = 0.88 = pB

mole fraction of B = partial pressure of B divided into the total gas pressure:

X(B) = 0.88 / ( 1.20 + 1.20 + 0.88 ) = 0.27

8 0
3 years ago
The chemical equation for the formation of ammonia is unbalanced.
galben [10]

Answer:

The answer to your question is 2 molecules

Explanation:

Unbalanced chemical reaction

                   H₂(g)   +   N₂(g)   ⇒   NH₃ (g)

         Reactants         Elements          Products

                2                      H                       3

                2                      N                       1

Balanced chemical reaction

                   3H₂(g)   +   N₂(g)   ⇒   2NH₃ (g)

         Reactants         Elements          Products

                6                      H                       6

                2                      N                       2

From the balanced chemical reaction we conclude that when 3 molecules of hydrogen react with one molecule of nitrogen, 2 molecules of ammonia will be formed.

4 0
3 years ago
Read 2 more answers
When The appearance of a system changes does the mass of the system also change why why not
seropon [69]
No, because the appearance has nothing to do with system as well as the fact that appearance is only how it looks

(Btw, that toga picture is like... ughhhh!) hope this helps you ♥︎☀︎☁︎♨︎

5 0
3 years ago
Read 2 more answers
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