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Pavlova-9 [17]
3 years ago
12

What is the following reaction?

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
7 0

Answer:

Decomposition

Explanation:

Decomposition is when the molecules split apart

AB --> A + B

2H2O3 --> H2O + O2

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Identify the limiting reactant in the reaction of iron and chlorine to form FeCl3, of 22.7 g of Fe and 37.2 g of Cl2 are combine
Mice21 [21]

Answer:

3.13 g of Fe remains after the reaction is complete

Explanation:

The first step to begin is determine the reaction:

2Fe + 3Cl₂ → 2FeCl₃

Let's find out the moles of each reactant:

22.7 g / 55.85 g/mol = 0.406 moles of Fe

37.2 g / 70.9 g/mol = 0.525 moles of Cl₂

Ratio is 2:3. 2 moles of iron react with 3 moles of chlorine

Then, 0.406 moles of iron will react with (0.406 . 3)/ 2 = 0.609 moles

We need 0.609 moles of chlorine when we have 0.525 moles, so as we do not have enough Cl₂, this is the limiting reactant.

The excess is the Fe. Let's see:

3 moles of chlorine react with 2 moles of Fe

Then, 0.525 moles of Cl₂ will react with (0.525 . 2) /3 = 0.350 moles

We need 0.350 moles of Fe and we have 0.406; as there are moles of Fe which remains after the reaction is complete, it is ok that Fe is the excess reagent.

0.406 - 0.350 = 0.056 moles of Fe still remains. We convert moles to mass:

0.056 mol . 55.85g / 1 mol = 3.13 g

5 0
3 years ago
Read 2 more answers
The electrons that are in the outermost electron shell, also known as the ____________ , have ____________ energy than those in
Tamiku [17]
The electrons that are in the outermost electron shell, also known as the valence shell, have more energy then those in the inner electron shells, I hope this helps<3
8 0
2 years ago
If a laser light is compose of photons each with an energy of 4.58 × 10−19 J, what is the photon energy of this light in units o
kap26 [50]

Answer : The photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

Solution :

Formula used :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = 4.58\times 10^{-19}J

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Now put all the given values in the above formula, we get:

4.58\times 10^{-19}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}

\lambda=4.3017\times 10^{-7}m=434.017\times 10^{-9}m=434.017nm=4.34\times 10^{-2}nm

conversion used : (1nm=1\times 10^{-9}m)

Therefore, the photon energy of this light in units of nanometers, (nm) is, 4.34\times 10^{-2}nm

5 0
3 years ago
A solution of Cuso, is labelled 1.743 M. How much Cuso, in grams, must be used to make
zepelin [54]

Answer:

Option A. 416.1 g.

Explanation:

Data obtained from the question include the following:

Molarity = 1.743 M

Volume = 1.4957 L

Mass of CuSO4 =..?

Next, we shall determine mole of CuSO4 present in the solution.

This is illustrated below:

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the mole CuSO4 present in the solution as follow:

Molarity = 1.743 M

Volume = 1.4957 L

Mole of CuSO4 =..?

Molarity = mole /Volume

1.743 = mole of CuSO4 /1.4957

Cross multiply

Mole of CuSO4 = 1.743 x 1.4957

Mole of CuSO4 = 2.607 moles

Finally, we shall convert 2.607 moles of CuSO4 to grams.

This can be obtained as follow:

Molar mass of CuSO4 = 63.55 + 32.06 + (16x4) = 159.61 g/m

Mole of CuSO4 = 2.607 moles

Mass of CuSO4 =..?

Mole = mass /molar mass

2.607 = mass of CuSO4 /159.61

Cross multiply

Mass of CuSO4 = 2.607 x 159.61

Mass of CuSO4 = 416.1 g

Therefore, 416.1 g of CuSO4 is needed to prepare the solution.

7 0
2 years ago
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PLEASE HELP ME I WOULD APPRECIATE IT SO MUCH!!!! ILL GIVE BRAINLIEST IF ITS CORRECT!
Mekhanik [1.2K]

Answer:

Graduated cylinder

Measuring cup

Explanation:

Hope this helps!

4 0
3 years ago
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