None of the energy is created nor destroyed
Answer:
The velocity of the man is 0.144 m/s
Explanation:
This is a case of conservation of momentum.
The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.
Mass of ball = 0.65 kg
Mass of the man = 54 kg
Velocity of the ball = 12.1 m/s
Before collision, momentum of the ball = mass x velocity
= 0.65 x 12.1 = 7.865 kg-m/s
After collision the momentum of the man and ball system is
(0.65 + 54)Vf = 54.65Vf
Where Vf is their final common velocity.
Equating the initial and final momentum,
7.865 = 54.65Vf
Vf = 7.865/54.65 = 0.144 m/s
It doesn't matter what the object's initial velocity is, or how long
the acceleration lasts. All that matters is the object's mass and
acceleration.
Force = (mass) x (acceleration) =
(5kg) x (15 m/s²) =
75 kg-m/s² = <em>75 newtons .</em>
Explanation:
The fluctuating sound heard when two objects vibrate with different frequencies is called beats. It is given that guitar string produces 3 beats/s when sounded with a 352 Hz tuning fork and 8 beats/s when sounded with a 357 Hz tuning fork.
It is assumed to find the vibrational frequency of the string.
For 3 beats/s, beat frequency can be :
352 - 3 or 352 + 3 = 349 Hz or 355 Hz
For 8 beats/s, beat frequency can be :
357 - 8 or 357 + 8 = 349 Hz or 365 Hz
It means that the vibrational frequency is 349 Hz.
M₁V₁ = m₂V₂
<span>KE = ½mV² </span>
<span>½m₁V₁² = 2*½m₂V₂² </span>
<span>m₁V₁ = m₂V₂ </span>
<span>½m₁V₁² = m₂V₂² </span>
<span>m₁/m₂ = V₂/V₁ </span>
<span>m₁/m₂ = 2V₂²/V₁² </span>
<span>V₂/V₁ = √(½m₁/m₂) </span>
<span>m₁/m₂ = √(½m₁/m₂) </span>
<span>squaring</span>
<span>(m₁/m₂)² = ½m₁/m₂ </span>
<span>2m₂m₁² = m₁m₂² </span>
<span>divide by m₁m₂ </span>
<span>2m₁ = m₂ </span>
<span>m₂/m₁ = 2
hope this helps</span>