Answer:
24 terminal zeros
Step-by-step explanation:
Here, we want to know the number of terminal zeros that the product if the integers above has
Terminal zeros refer to the zeros at the right of the last non zero digits
The product we are dealing with is;
80^16 * 75^8
80^16 itself has 16 terminal zeros
while 75^8 should have 8 terminal zeros
So the total number of expected terminal zeros is simply the addition of both terminal zeros and that gives 16 + 8 = 24 terminal zeros
1)
= 24z^7
answer
A. 24z^7
2)
= 24 x^2y^9
answer
D. 24 x^2y^9
3)
=w^12z^18
answer
C. w^12z^18
4)
= 4x^6
answer
B. 4x^6
Answer:
We should get a 3 about 5 times
Step-by-step explanation:
Possible outcomes 1,2,3,4,5,6
P(3) = number of 3's / total = 1/6
Expect a 3 = number of rolls * probability of a three
= 30 * 1/6
=5
Answer:
20
Step-by-step explanation:
The question is simply asking you to plug 6 into the function.
Answer: x + 4 = 64
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