Answer:
hello the diagram related to this question is missing attached below is the missing diagram
Answer :
The magnitude of the electric field = 4KQ / L^2
direction = 45° east to south
Explanation:
The magnitude of the electric field = 4KQ / L^2
direction = 45° east to south
As the rollercoaster goes up. kinetic energy changes to gravitational potential energy. When it moves back down, gpe changes back to ke.
Answer:
add text fully or atleast add book name edition . solution is in picture. chk pictures ignore b part
Explanation:
The statement that is true is a. the large bran muffin contains more heat energy. This statement holds true because of the equation E=mc2. E= Energy, m=mass and c=the speed of light. Although both muffins are at room temperature, the larger will theoretically have more heat energy because it has more mass.
Complete Question
The complete question is shown on the first uploaded image
Answer:
the compass direction of the resultant displacement is
south of west
Explanation:
Generally using cosine we can obtain the resultant R as follows

=> 
=> 
We can obtain the direction of the resultant by first using sine rule to obtain angle C as follows

=> ![C= sin ^{-1} [\frac{A * (sin 70)}{R} ]](https://tex.z-dn.net/?f=C%3D%20%20sin%20%5E%7B-1%7D%20%5B%5Cfrac%7BA%20%2A%20%20%28sin%2070%29%7D%7BR%7D%20%5D)
=> ![C = sin ^{-1} [\frac{20 * (sin 70)}{19.48} ]](https://tex.z-dn.net/?f=C%20%3D%20%20sin%20%5E%7B-1%7D%20%5B%5Cfrac%7B20%20%2A%20%20%28sin%2070%29%7D%7B19.48%7D%20%5D)
=> 
Then the direction is obtained as

=> 
=> 
Hence the compass direction of the resultant displacement is
south of west