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andrew-mc [135]
3 years ago
9

Find the distance in nm between two slits that produces the first minimum for 410-nm violet light at an angle of 14.5°.

Physics
2 answers:
docker41 [41]3 years ago
8 0

Answer:

Explanation:

wavelength, λ = 410 nm

Angle, θ = 14.5°

The formula used for the distance between the two slits for minima is given by

dSin\theta =\left (m+\frac{1}{2}  \right )\lambda

for first order minima, m = 0

d Sin 14.5 = 0.5 x 410

d = 818.76 nm

Galina-37 [17]3 years ago
5 0

Answer:

820 nm

Explanation:

We are given that

Wavelength=\lambda=410 nm

\lambda=410\times 10^{-9} m

1nm=10^{-9} m

\theta=14.5^{\circ}

For first minimum therefore

m=0

We know that for destructive interference

(m+\frac{1}{2})\lambda=dsin\theta

Substitute the values

(0+\frac{1}{2})\times 410\times 10^{-9}=dsin 14.5

d=\frac{410\times 10^{-9}}{2\times sin 14.5}

d=820\times 10^{-9} m=820 nm

Hence, the distance between two slits that produces the first minimum=820 nm

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