Answer: -32
You are taking away from "withdrawal"
Answer:
-5w^9.
Step-by-step explanation:
These two terms are what we call, 'like terms'. This means that they are terms whose variables and exponents are the same. 14w^9- 19w^9 have the variable w^9 in common.
In these cases, all we do is use the coefficients (the number in front of the variable). Hence, 14w^9- 19w^9, quite literally turns into, 14-19. If we complete the sum, 14-19= -5. Put it all together, we have -5w^9.
Hope this helps!
There's no question there. You didn't attach the pic
Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by

We will approximate this distance using the relation

dx = 26 - 25 = 1
T' = 2.5 + x
Therefore

This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5×
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 × 
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance =
× 100
% change in stopping distance = 7.34 %