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3 years ago

The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)

Physics

2 answers:

docker41 [41]3 years ago

8 0

The are is called a magnetic field.

choli [55]3 years ago

6 0

That's the description of an "magnetic field".

The way your question is worded, it sounds like there's an end to the field of a magnet ... it exists only up to a certain distance, and past that, it doesn't exist. This is not true. Yes, the field of a magnet is weaker as you get farther away from it, and eventually you can get so far away that you can't detect or measure it. But it's still there, and we can always calculate how strong or weak it is, at ANY distance, even in a middle-school classroom on the far side of a different galaxy from ours !

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25

torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is $1.474\times10^{-7}\ C/m^2$

The capacitance is $4.484\times10^{-12}\ F$

The charge on each plate is $112.1\times10^{-12}\ C$

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

$E=\dfrac{V}{d}$

Put the value into the formula

$E=\dfrac{25.0}{1.50\times10^{-3}}$

$E=16666.66\ V/m$

We need to calculate the charge density

Using formula of charge density

$\sigma=E\times\epsilon_{0}$

Put the value into the formula

$\sigma=16666.66\times8.85\times10^{-12}$

$\sigma=1.474\times10^{-7}\ C/m^2$

We need to calculate the capacitance

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}$

$C=4.484\times10^{-12}\ F$

We need to calculate the charge

Using formula of charge

$q=CV$

Put the value into the formula

$q=4.484\times10^{-12}\times25.0$

$q=112.1\times10^{-12}\ C$

Hence, The electric field is 16666.66 V/m.

The surface charge density is $1.474\times10^{-7}\ C/m^2$

The capacitance is $4.484\times10^{-12}\ F$

The charge on each plate is $112.1\times10^{-12}\ C$

8 0

3 years ago

The Southwest Indian Ridge, shown in red, moves at an average rate of 20 mm/year, making it among the ultraslow spreading ridges

blagie [28]

v = average speed of movement of the Southwest Indian Ridge = 20 mm/year

d = distance moved by the Southwest Indian Ridge = 100 mm

t = number of years required to move distance "d"

distance traveled is given as

d = v t

inserting the above values in the formula

100 mm = (20 mm/year) t

dividing both side by 20 mm/year

t = 100 mm/(20 mm/year)

t = 5 years

7 0

3 years ago

Read 2 more answers

Seema knows the mass of a basketball. What other information is needed to find the ball’s potential energy? the volume and heigh

Wewaii [24]

It is because the potential energy is similar to MgH.

When it comes to MgH, it means mass, gravity and height respectively.

By using the value of acceleration, seema will find the potential energy of a ball.

7 0

4 years ago

Read 3 more answers

A car travels 45 km due north and 70 km west. What is the car's displacement?

Elis [28]

Answer:

Explanation:

7 0

3 years ago

A tablecloth can be pulled out from underneath a fully set table without breaking plates or glassware. The reason is that the ob

bekas [8.4K]

Answer:

newtons law of force

newtons law of force explains that something may or can or canot move depending on the objexts mass.

6 0

3 years ago