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3 years ago

The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)

Physics

2 answers:

docker41 [41]3 years ago

8 0

The are is called a magnetic field.

choli [55]3 years ago

6 0

That's the description of an "magnetic field".

The way your question is worded, it sounds like there's an end to the field of a magnet ... it exists only up to a certain distance, and past that, it doesn't exist. This is not true. Yes, the field of a magnet is weaker as you get farther away from it, and eventually you can get so far away that you can't detect or measure it. But it's still there, and we can always calculate how strong or weak it is, at ANY distance, even in a middle-school classroom on the far side of a different galaxy from ours !

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The voltage leaving the secondary coil of a transformer is equal to 240 V. The secondary coil is wrapped 8 times around the core

Lina20 [59]

The initial voltage at the primary= 750 V

Explanation:

for a transformer

Es/ Ep= Ns/ Np

Es= secondary voltage= 240 V

Ep= primary voltage

Ns= number of turns in the secondary=8

Np= Number of turns in the primary=25

so 240/Ep=8/25

Ep=750 V

7 0

3 years ago

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The equation for density is mass divided by volume if you pack more mass into a certain volume the density will?

Natali [406]

If you pack more mass into a certain volume, the density will increase.

8 0

3 years ago

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Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east

barxatty [35]

Answer:

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5 0

3 years ago

A race car is one lap behind the lead race car when the lead car has 55 laps to go in a race. If the speed of the lead car is 62

ella [17]

Answer:

The second car must go with a speed of 63.43 m/sec

Explanation:

Speed V of lead car = 62.3 m/sec

Distance S = 55 laps = 55 ×400 meters=22000 m

We know

S = V × t

So,

t= S/V

We put values of S and V here, we get

t=22000/62.3

t= 353.1 sec

So in 353.1 sec the second car which is one lap behind - must go a distance of 55+1=56 laps or 56×400 m = 22400 meters to catch the lead car before it finishes.

i-e for second car

Distance S= 22400m

Time t = 353.1 sec

V= ?

using again

S=Vt

we get

V= S/t

V= 22400/353.1= 63.43 m/sec

7 0

4 years ago

A 0.300 kg mass is attached to

scoundrel [369]

Answer:

0.144 J

Explanation:

From the question above,

Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring

E' = E.k+Ep...................... Equation 1

Ek = E'-Ep......................... Equation 2

Where E' = total elastic energy, E.k = kinetic energy, E.p = potential energy.

E' = 1/2ke² = 1/2(26.6)(0.12²) = 0.19152 J.

Ep = 1/2ke² = 1/2(26.6)(0.06²)

Ep = 0.04788 J

Therefore,

Ek = 0.19152-0.04788

Ek = 0.144 J

8 0

3 years ago