Answer:
nail will stop after traveling 1000 m
Explanation:
We have given mass m = 50 gram = 0.05 kg
Frictional force which is used to stop the mass F = 62.5 kN
Initial velocity is given u = 50 m/sec
From newton's law force is equal to F = ma, here m is mass and a is acceleration
So 
As finally nail stops so final velocity v = 0 m/sec
From third equation of motion 
So 
s = 1000 m
So nail will stop after traveling 1000 m
Answer:
(a) 3.13 m/s
(b) 9.9 m/s
(c) 7.73 m/s
Explanation:
u = 0 m/s, g = 9.8 m/s^2
Let v be the velocity of ball as it hit the ground.
(a) h = 0.5 m
Use third equation of motion.
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 0.5
v^2 = 9.8
v = 3.13 m/s
(b) h = 5 m
Use third equation of motion.
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 5
v^2 = 98
v = 9.9 m/s
(c) h = 10 feet = 3.048 m
Use third equation of motion.
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 3.048
v^2 = 59.74
v = 7.73 m/s
Answer:
L = 2774.4 
Explanation:
Using the formula
L = mvr
Where L is angular momentum
m is mass
v is velocity
r is radius
m= 51kg , v=17m/s , r=3.2m
L = 51×17×3.2
L = 2774.4
"Constant change of direction" simply means on a curve.
The examples provided don't show a durn thing.
