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3 years ago

What is the safety rules?

Physics

2 answers:

krek1111 [17]3 years ago

6 0

Answer:

helping because if a fire you need to be a good person even if you hate somone

Black_prince [1.1K]3 years ago

5 0

Answer:

Quick question do you mean what are some safety rules

Explanation:

Crosswalk, Stop sign,

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Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia

sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

$s_A = -6 + 9t$

$s_B = 5 - 8t$

When A an B meets, they are at the same position and at the same time. So

$s_A = s_B$

$-6 +9t = 5 - 8t$

$17t = 5 + 6 = 11$

$t = 11/17 = 0.647 s$

$s_A = -6 + 9*0.647 = -0.176 m$

So where they meet is 0.176m from the flagpole, westward.

5 0

2 years ago

3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?

ZanzabumX [31]

Answer:

$E_s = 277.13V$

Explanation:

Given

$Load\ Voltage = 480V$

Required

Determine the voltage dropped in each stage.

The relation between the load voltage and the voltage dropped in each stage is

$E_l = E_s * \sqrt3$

Where

$E_l = 480$

So, we have:

$480 = E_s * \sqrt3$

Solve for $E_s$

$E_s = \frac{480}{\sqrt3}$

$E_s = \frac{480}{1.73205080757}$

$E_s = 277.128129211$

$E_s = 277.13V$

<em>Hence;</em>

<em>The voltage dropped at each phase is approximately 277.13V</em>

5 0

2 years ago

Rank the following meteorites in terms of their age, from youngest to oldest:1) a meteorite containing 500 238U isotopes and 100

satela [25.4K]

Answer:

Explanation:

When 238U which is radioactive turns into 206Pb , it becomes stable and no further disintegration is done . Hence in the initial period ratio of 238U undecayed and 206Pb formed will be very high because no of atoms of 238U in the beginning will be very high. Gradually number of 238U undecayed will go down and number of 206Pb formed will go up . In this way the ratio of 238U and 206Pb in the mixture will gradually reduce to be equal to one or even less than one .

In the given option we shall calculate their raio

1 ) ratio of 238U and 206Pb = 5

2 ) ratio of 238U and 206Pb = 4

3 )ratio of 238U and 206Pb = 1

4 ) ratio of 238U and 206Pb = 20

5 )ratio of 238U and 206Pb = 3

lowest ratio is 1 , hence this sample will be oldest.

Ranking from youngest to oldest

4 , 1 , 2 , 5 , 3 .

4 0

3 years ago

Which part is not necessary to complete a circuit

Levart [38]

A SWITCH I THINK??..

6 0

3 years ago

Read 2 more answers

Which of the following statements are true? The internal resistance of a battery decreases with decreasing temperature. A batter

Eddi Din [679]

Answer:

Option B

Explanation:

The obstruction offered by the battery is known as its internal resistance. Electricity is produced by the chemical reactions inside the battery. The pace of the responses is straightforwardly relative to the temperature and the power delivered by the battery increments. In this way, the inward opposition of the battery increments as diminishing the temperature.
The battery is a gadget which generates electrical energy by the chemical reactions that takes place inside it.

In this way, the announcement a battery is a gadget that produces electricity by the transformation of chemical energy into electrical energy is valid.
The potential difference between the terminals of a battery, when no current is streaming into an outer circuit is called emf of the battery and if the potential distinction is measure when the current is streaming into the outside circuit is called terminal voltage .
The battery attempts to move the negative charge from the low potential terminal to the high potential terminal of the battery. The potential vitality of the negative charges is high at the lower potential terminal and the potential vitality of the negative charge is low at the high potential terminal. Along these lines, the battery attempts to move the charges from high potential terminal to low potential terminal.

7 0

2 years ago