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mixer [17]
3 years ago
13

What is the safety rules?

Physics
2 answers:
krek1111 [17]3 years ago
6 0

Answer:

helping because if a fire you need to be a good person even if you hate somone

Black_prince [1.1K]3 years ago
5 0

Answer:

Quick question do you mean what are some safety rules

Explanation:

Crosswalk, Stop sign,

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If the distance of a galaxy is 2,000 Mpc, how many years back into the past are we looking when we observe this galaxy
ruslelena [56]

The age of the galaxy when we look back is 13.97 billion years.

The given parameters:

  • <em>distance of the galaxy, x = 2,000 Mpc</em>

According Hubble's law the age of the universe is calculated as follows;

v = H₀x

where;

H₀ = 70 km/s/Mpc

T = \frac{x}{V} \\\\T = \frac{x}{xH_0} \\\\T = \frac{1}{H_0} \\\\T = \frac{1}{70 \ km/s/Mpc} \\\\T = \frac{1 \ sec}{70 \times 3.24 \times 10^{-20} } \\\\T = 4.41 \times 10^{17} \ sec\\\\T = \frac{4.41 \times 10^{17} \ sec\  \times \ years}{3600 \ s \ \times\  24\ h\  \times \ 365.25 \ days} \\\\T = 1.397  \times 10^{10} \ years\\\\T = 13.97 \ billion \ years

Thus, the age of the galaxy when we look back is 13.97 billion years.

Learn more about Hubble's law here: brainly.com/question/19819028

8 0
2 years ago
A student is getting ready to go on a bike ride, but her bike back tire is flat! She connects a pump to the valve and adds air t
Mariana [72]
Wheres the answer below?
4 0
2 years ago
If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do
geniusboy [140]

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

8 0
3 years ago
A family goes on a walk beside a large river. What would most likely happen to the river if the oceans did not exist?
Setler79 [48]

it would be all dried up :((

6 0
3 years ago
Read 2 more answers
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid
Setler79 [48]

Answer:

a)

- 7.04\times10^{11} J

b)

5.03\times10^{5} N

Explanation:

a)

m = mass of the asteroid = 43000 kg

v_{o} = initial speed of asteroid = 7600 m/s

v = final speed of asteroid = 5000 m/s

W = Work done by the force on asteroid

Using work-change in kinetic energy theorem

W = (0.5) m (v^{2} - v_{o}^{2})\\W = (0.5) (43000) (5000^{2} - 7600^{2})\\W = - 7.04\times10^{11} J

b)

F = magnitude of force on asteroid

d = distance traveled by asteroid while it slows down = 1.4 x 10⁶ m

Work done by the force on the asteroid to slow it down is given as

W = - F d\\- 7.04\times10^{11} = - F (1.4\times10^{6})\\F = 5.03\times10^{5} N

4 0
3 years ago
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