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VMariaS [17]
3 years ago
6

Will mark brainliest if answered fast enough.

Chemistry
2 answers:
MrRa [10]3 years ago
6 0

Answer:

1,3,5,6

Explanation:

I took the test

stepan [7]3 years ago
3 0

Answer:

the answer is 1,3,5 and 6 :)

Explanation:

You might be interested in
What kind of reaction occurs when you mix aqueous solutions of barium sulfide and sulfuric acid? what kind of reaction occurs wh
My name is Ann [436]

The kind of reaction that occurs when you mix aqueous solutions of barium sulfide and sulfuric acid is a precipitation reaction.

<h3>Further Explanation</h3>
  • The chemical reaction between Ba(OH)2(aq) and H2SO4(aq) is given by;

Ba(OH)₂(aq) + H₂SO4(aq) --> BaSO₄(aq) + 2H₂O(l)

  • This is a type of precipitation reaction, where a precipitate is formed after the reaction, that is Barium sulfate.
<h3>Other types of reaction</h3><h3>Neutralization reactions </h3>
  • These are reactions that involve reacting acids and bases or alkali to form salt and water as the only products.
  • For example a reaction between sodium hydroxide and sulfuric acid.

NaOH(aq) + H₂SO₄(aq) → Na₂SO₄(aq) + H₂O(l)

<h3>Displacement reactions</h3>
  • These are reactions in which a more reactive atom or ion displaces a less reactive ion from its salt.

Mg(s) + CuSO₄(aq) → MgSO₄(aq) + Cu(s)

<h3>Redox reactions </h3>
  • These are reactions that involve both reduction and oxidation occuring simultaneously durin a chemical reaction.
  • For example,

Mg(s) + CuSO₄(aq) → MgSO₄(aq) + Cu(s)

  • Magnesium atom undergoes oxidation while copper ions undergoes reduction.
<h3>Decomposition reactions</h3>
  • These are type of reactions that involves breakdown of a compound into its constituents elements.
  • For example decomposition of lead nitrate.

Pb(NO3)2(S) → PbO(s) + O2(g) + NO2(g)

Keywords: Precipitation

<h3>Learn more about: </h3>
  • Precipitation reaction: brainly.com/question/11194650
  • Examples of precipitation reactions: brainly.com/question/11194650
  • Neutralization reactions brainly.com/question/3243813

Level: High school

Subject: Chemistry

Topic: Chemical reactions

Sub-topic: Precipitation reactions

3 0
4 years ago
Read 2 more answers
A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo
zheka24 [161]

Explanation:

The given data is as follows.

         Width of Styrofoam = 24.0 cm

          Length of Styrofoam = 36.0 cm

          Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

                  Volume = length × width × height

                                =  (36.0 × 24.0 × 5.0) cm^{3}

                                 = 4320 cm^{3}

or,                             = 4.32 \times 10^{3} cm^{3}

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

          24.0 cm × 36.0 cm × 2.0 cm

         = 1.73 \times 10^{3} cm^{3}

Hence, mass of displaced water is as follows.

                 mass = density × volume

                           = 1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}

                           = 1.73 \times 10^{3} g

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

             Mass of water displaced = mass of book + mass of Styrofoam

                  1.73 \times 10^{3} g = 1500 g + mass of Styrofoam

                   (1730 - 1500) g = mass of Styrofoam

                   mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

                   Density = \frac{mass}{volume}  

                                 = \frac{230}{4.32 \times 10^{3} cm^{3}}

                                 = 53.24 \times 10^{-3} g cm^{-3}

Thus, we can conclude that the density of Styrofoam is 53.24 \times 10^{-3} g cm^{-3}.

4 0
3 years ago
(a) a 0.2 m potassium hydroxide solution is titrated with a 0.1 m nitric acid solution. (i) balanced equation: (ii)what would be
Stells [14]

\text{KOH} (aq) + \text{HNO}_3 (aq) \to \text{KNO}_3 (aq) + \text{H}_2\text{O} (l)

The solution shall contain only \text{KNO}_3 (aq) (and water) at the equivalence point. Both potassium hydroxide and nitric acid exist as strong electrolytes. As a result,  \text{KNO}_3 (aq), the salt derived from a reaction between the two species would undergo hydrolysis of a negligible extent. This neutralization reaction therefore be neutral at the equilibrium point.

The question states that the solution is "titrated with a ... nitric acid solution" indicating that \text{HNO}_3 is added to the initially-basic solution. PH value of the solution would keep decreasing as the volume of the acid added increases. The final solution would be acidic as it contains not only water and \text{KNO}_3 (aq), but some \text{HNO}_3 as well. Bromothymol blue would therefore demonstrates a yellow color, the color it present in an acidic solution, at the end of the titration.

5 0
3 years ago
Planetesimals are made from <br><br> A. Rock<br><br> B. Gas<br><br> C. Stars<br><br> D. Clouds
White raven [17]
A )rock is correct answer
3 0
3 years ago
Read 2 more answers
A gas mixture contains 0.700 mol of N2, 0.300 mol of H2, and 0.400 mol of CH4. Calculate the pressure of the gas mixture and the
Nitella [24]

Answer:

Pressure of the gas mixture: 4.30 atm

Partial pressure N₂ = 2.15 atm

Partial pressure H₂ =  0.91 atm

Partial pressure CH₄ = 1.23 atm

Explanation:

To determine partial pressure we sum the total moles in order to find out the total pressure

We can work with mole fraction

We apply the Ideal Gases Law

0.700 N₂ + 0.300 H₂ + 0.400 CH₄ = 1.4 moles

We replace data  → P . V = n . R .T

T° must be at K →  27  °C + 273 = 300 K

P . 8 L = 1.4 mol . 0.082 L.atm/mol.K  . 300 K

P = ( 1.4 mol . 0.082 L.atm/mol.K  . 300 K) / 8 L = 4.30 atm (Total pressure)

We apply the mol the fraction for the partial pressure

Moles x gas / total moles = partial pressure x gas / total pressure

Mole fraction N₂ → 0.700 /1.4 = 0.5

Partial pressure N₂ = 0.5 . 4.30 atm =2.15 atm

Mole fraction H₂  →  0.300 / 1.4 = 0.21

Partial pressure H₂ = 0.21 . 4.30 atm = 0.91 atm

Mole fraction CH₄ → 0.400 /1.4 = 0.28

Partial pressure CH₄ = 0.28 . 4.30 atm =1.23 atm

7 0
3 years ago
Read 2 more answers
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