Answer: The line is AB and the plane is ABD, the first option is the correct one.
Step-by-step explanation:
Ok, first some definitions.
A line is any line that crosses two colinear points. Particularly, you can see in the graph that the line crosses through A and B, so the line is AB.
A plane needs 3 non-colinear points (if the points where colinear, then the points may define a line). Other definition of plane is "a line and a point that is not in the line"
So, if our line is AB, then the possible planes are:
ABC and ABD.
then the correct option is:
Line AB and plane ABD, so the correct option is the first one.
Answer:
The equation of a parallel line in point-slope form would be y - 3 = -8(x + 3)
Step-by-step explanation:
To find this, we must first note that the original slope is -8. Parallel lines have the same slope, so we know that the new line will also have the slope of -8.
Given this information, we can use the point and slope and put them into the base form of point-slope form.
y - y1 = m(x - x1)
y - 3 = -8(x - -3)
y - 3 = -8(x + 3)
1. By the chain rule,
I'm going to switch up the notation to save space, so for example, 
is shorthand for 
.
We have
Similarly,
where
To capture all the partial derivatives of 
, compute its gradient:
2. The problem is asking for and 
. But 
is already a function of 
, so the chain rule isn't needed here. I suspect it's supposed to say "find 
and 
" instead.
If that's the case, then
as the hint suggests. We have
Putting everything together, we get
