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marin [14]
3 years ago
9

Barium acetate, Ba(C2H3O2)2, is a common barium salt that is highly poisonous. It was featured in a 2001 episode of Forensic Fil

es, which recounted the murder of a man by his teenaged daughter. The LD50 (the dose that will be lethal to 50% of people that consume the compound) for barium acetate is 921 mg/kg of body weight.
A sample that contains 1.98x10^24 carbons atoms has a mass of ____ grams.
Chemistry
1 answer:
aleksley [76]3 years ago
8 0

Answer:

209.68

Explanation:

The only number that is relevant (though the rest are quite interesting) is the last one 1.98 * 10^24

1 mole of Barium Acetate Contains 6.02*10^23 particles.

There are 4 moles of carbon to every mole of Barium Acetate.

1.98 * 10^24 atoms / (4*6.02*10^23)

0.8223 moles of Ba(C2H3O2)2

Ba =                 137

4C = 4*12          48

6H = 6*1              6

4O = 4*16           64

1mole                 255 grams

0.8223 * 255 = 209.68 grams  

I have used rounded masses for these elements depending on the periodic table you use. Go through the question with your masses to get a more accurate answer. My answer will not differ by much. It is a guide.

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A mixture of hydrogen and argon gases is maintained in a 6.47 L flask at a pressure of 3.43 atm and a temperature of 85 °C. If t
11Alexandr11 [23.1K]

Answer:

The mixture contains 8.23 g of Ar

Explanation:

Let's solve this with the Ideal Gases Law

Total pressure of a mixture = (Total moles . R . T) / V

We convert T° from °C to K → 85°C + 273 = 358K

3.43 atm = (Moles . 0.082 L.atm/mol.K . 358K) / 6.47L

(3.43 atm . 6.47L) / (0.082 L.atm/mol.K . 358K) = Moles

0.756= Total moles from the mixture

Moles of Ar + Moles of H₂ = 0.756 moles

Moles of Ar + 1.10 g / 2g/mol = 0.756 moles

Moles of Ar = 0.756 moles - 0.55 moles H₂ → 0.206

We convert the moles to g → 0.206 mol . 39.95 g / 1 mol = 8.23 g

8 0
3 years ago
Read 2 more answers
Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-1
jekas [21]

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

Explanation: pKa= -log(Ka)= 12.38. PH + pOH = 14.00

8 0
3 years ago
Calculate the volume in mL of a 0.708 M KOH solution containing 0.098 mol of solute
Olenka [21]
Molarity = mol/liter

0.708M = 0.098mol/L
Rearrange to find L:
0.098mol/0.708M = .138L

For every liter there is 1000 mL:
.138L • 1000mL =138mL KOH
7 0
3 years ago
if you are using a formula where you need the change in temperature, explain why it is not important whether your temperatures a
alexandr1967 [171]

Answer:

This is because, Kelvins and Celcius degrees both agree at fixed points i.e; the lower fixed point and upper

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3 years ago
What piece of equipment is used to measure: length
avanturin [10]

Answer:

Ruler

Explanation:

Ruler and eraser kakgjwjeigidiifigig

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