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cestrela7 [59]
3 years ago
13

7. Some of the following sublevels do not exist. Cross out the ones that are not real.

Chemistry
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

1f 3f 5g 1p 2d

Explanation:

There is only 4f and 5f orbitals.

G is not an orbital.

P orbital starts with 2p

D orbital starts with 3d

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Why do you need to use soap when you wash oil from your hands
yawa3891 [41]

Answer:

Germs stick to the oil on your hands, and washing with just water doesn't work because oil and water don't mix, but soap dislodges the germs and oil from your hands

Explanation:

3 0
3 years ago
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The compound H2O is an example of a(n)
SashulF [63]
The answer you are looking for is water.
5 0
3 years ago
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Zachary adds 9.7 g to 1.114 g.<br> How many significant figures should his answer have?
makvit [3.9K]
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
5 0
3 years ago
Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the ne
mixer [17]

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

<em>Where E</em>⁰<em>= 0.4249V</em>

<em>E(Cell) = -(-0.0019V) -Measured value-</em>

<em>[Cu2+] = 1M</em>

<em />

Replacing:

0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)

-0.423V = - 0.0296 • log (1M/[Ag+]²)

14.29 = log (1M/[Ag+]²)

1.95x10¹⁴ = 1M / [Ag+]²

[Ag+]² = 5.12x10⁻¹⁵M

7.16x10⁻⁸M = [Ag+]

5 0
2 years ago
Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with
VladimirAG [237]

Answer:

7.3 g (NH₄)₃PO₄

Explanation:

The balanced equation for the reaction is:

H₃PO₄ +  3 NH₃ ----> (NH₄)₃PO₄

To find the mass of ammonium phosphate ((NH₄)₃PO₄) produced, you need to (1) convert grams NH₃ to moles NH₃ (via the molar mass from the periodic table), then (2) convert moles NH₃ to moles (NH₄)₃PO₄ (via mole-to-mole ratio from balanced equation), and then (3) convert moles (NH₄)₃PO₄ to grams (NH₄)₃PO₄ (via molar mass from periodic table). Make sure to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs because the given value (2.5 grams) has 2 sig figs.

Molar Mass (NH₃): 14.01 g/mol + 3(1.008 g/mol)

Molar Mass (NH₃): 17.034 g/mol

Molar Mass ((NH₄)₃PO₄):

3(14.01 g/mol) + 12(1.008 g/mol) + 30.97 g/mol + 4(16.00 g/mol)

Molar Mass ((NH₄)₃PO₄): 149.096 g/mol

2.5 g NH₃          1 mole NH₃        1 mole (NH₄)₃PO₄             149.096 g
---------------  x  --------------------  x  ---------------------------  x  --------------------------
                            17.034 g             3 moles NH₃              1 mole (NH₄)₃PO₄

=  7.3 g (NH₄)₃PO₄

8 0
2 years ago
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