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3 years ago

When will Le Chatelier's principle come into effect?

Chemistry

2 answers:

frutty [35]3 years ago

7 0

The answer is B, i have the same class on plato. the principal only comes into effect when the equilibrium is disturbed

alex41 [277]3 years ago

4 0

Answer: Option (b) is the correct answer.

Explanation:

According to Le Chatelier's principle, when a system in equilibrium is brought to any change in concentration, temperature or pressure then the equilibrium will shift to the direction opposing the change.

Therefore, we can conclude that when a reaction has reached chemical equilibrium then Le Chatelier's principle will come into effect.

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A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is th

trasher [3.6K]

Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K$

Putting values in above equation, we get:

$\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm$

Thus the new pressure, if volume and amount of gas do not change is 2.40 atm

5 0

3 years ago

The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th

Alona [7]

Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_2$ = rate of reaction at $T_2$

$K_1$ = rate of reaction at $T_1$

$Ea$ = activation energy of the reaction

R = gas constant = 8.314 J/K mol

$E_a=300 kJ/mol=300,000 J/mol$

$T_2=625^oC=898.15 K,T_1=525^oC=798.15 K$

$\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]$

$\log (\frac{K_2}{K_1})=2.185666$

$K_2=153.344\times K_1$

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

4 0

3 years ago

In the periodic table, the elements that are adjacent to the "stair step" are called _____. actinide series nonmetals metalloids

yawa3891 [41]

Answer:-

Metalloids

Explanation:-

The stair step line is a line in the periodic table that divides the metals on one side and the non metals on the other side. So the elements which lie on the stair step line must have properties in between those exhibited by the metals and those by the non metals.

Such elements we know are called metalloids. Thus In the periodic table, the elements that are adjacent to the "stair step" are called metalloids.

5 0

3 years ago

Na CN + HCl ->?? <br><br>Thanks for your time

Tom [10]

Sodium chloride and prussic acid are formed

NaCN+HCl→NaCl+HCN

4 0

2 years ago

2CO(g)+O2 (g) =2CO2(g)

Ronch [10]

Answer:

6.76 moles.

Explanation:

2CO(g)+O2 (g) =2CO2(g)

When 2 CO mols were reacted with excess O2 then 2 mols of CO2 is created.

Therefore if 6.76 moles reacted, same number of CO2 will be created.

4 0

3 years ago