What is the correct name for SO3?

A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

4 years ago

2C4H10 + 13O2 Right arrow. 8CO2 + 10H2O What is the mole ratio of butane to carbon dioxide?

Zielflug [23.3K]

2C4H10 + 13O2 Right arrow. 8CO2 + 10H2O

What is the mole ratio of butane to carbon dioxide?

ANSWER:

Butane is an organic compound with the formula C4H10 and carbon dioxide is compound (gas) with the formula CO2. So, the balanced coefficient of butane is 2, and that of carbon dioxide is 8. According to thid, the mole ratio of butane to carbon dioxide is 2:8 or 1:4.

7 0

3 years ago

I NEED HELP ASAP! :)

cluponka [151]

Answer:

When adding the measurements 42.1014g + 190.5g, the answer has seven significant figures.

When dividing the measurements 400g/32.2 cm^3, the answer has ten significant figures.

Explanation:

7 0

3 years ago

What kind of evidence can you use to determine if a chemical reaction has occured?

Harman [31]

Use your senses, so sound, smell( pls waft), change in color or tempurature, bubbles, or light

8 0

4 years ago

Read 2 more answers

PLEASE HELP ME ASAP What is the volume of 28.9 g of mercury if the density is 13.8 g/mL? *

strojnjashka [21]

Answer:

2.09 mL

Explanation:

density = mass/volume

13.8 = 28.9/v

13.8v = 28.9

v = 2.09 mL

8 0

3 years ago