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nexus9112 [7]
3 years ago
8

Please answer soon

Physics
1 answer:
kupik [55]3 years ago
3 0
Equal to the force of friction exerted upon the car . ( how this is right )
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If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?
nadezda [96]

To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

F = ma\rightarrow F =mg

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

W= (10kg)(9.8)

W = 98N

Since the rope is taut and does not break, the net force on the rope will be zero.

\sum F = 0

T-W = 0

T = W

T = 98N

Therefore the tensile force in the rope is 98N

8 0
3 years ago
Can an object have both kinetic energy and gravitational potential energy? Explain.
konstantin123 [22]
Yes, for example a plain is moving so it has kinetic energy, it is also high above the ground so it has gravitational potential energy
7 0
3 years ago
A parallel-plate capacitor is constructed from two aluminum foils of 1 square centimeter area each placedon both sides of a rubb
Svet_ta [14]

Answer:

The voltage will be 0.0125V

Explanation:

See the picture attached

4 0
4 years ago
Define: exitstentialism
sp2606 [1]
A philosophical theory or approach that emphasizes that the existence of the individual person as a free and responsible agent determining their own development through acts of the will.
7 0
3 years ago
A mass of 156.7g of Helium gas at an initial temperature of 35.73°C and at an initial absolute pressure of 3.55 atm undergoes an
AlexFokin [52]

Answer:

Explanation:

Moles of helium ( n ) = 156.7 / 4 = 39.175

Temperature T₁ = 35.73 +273 = 308.73 K

Volume V₁ = V

Pressure P₁ = 3.55 atm

V₂ =1.75 V

a ) For isothermal change

P₁ V₁ = P₂V₂

P₂ = P₁ V₁ / V₂

= 3.55 X V / 1.75 V

= 2.03 atm.

b ) Work done by the gas = nRT ln(V₂/V₁)

= 39.175 X 8.321 X 308.73 X ln 1.75

= 56318.8 J

Work done on the gas = - 56318.8 J

c ) Since there is no change in temperature , internal energy of gas is constant

Q = ΔE + W

ΔE  = 0

Q = W

Work done by gas = heat absorbed

heat absorbed = 56318.8 J

d ) Change in the internal energy of gas is zero because temperature is constant.

6 0
4 years ago
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