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ANEK [815]
2 years ago
5

Which of the following is the cause of the change of seasons? A) the distance of a place from the Equator B) prevailing winds bl

owing across land or water C) the tilt of the Earth’s axis D) the rotation of the Earth
Physics
1 answer:
cupoosta [38]2 years ago
3 0
C. the tilt of the earth's axis <span />
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A 3.63.kgkg chihuahua charges at a speed of 3.3m/s3.3m/s. What is the magnitude of the average force needed to bring the chihuah
sergiy2304 [10]

Answer:

23.96 N

Explanation:

From the question given above, the following data were obtained:

Mass of Chihuahua (m) = 3.63 kg

Velocity (v) = 3.3m/s

Time (t) = 0.50 s

Force (F) =?

Next, we shall determine the acceleration of the Chihuahua. This can be obtained as follow:

Velocity (v) = 3.3m/s

Time (t) = 0.50 s

Acceleration (a) =?

a = v/t

a = 3.3/0.5

a = 6.6 m/s²

Thus, the acceleration of the Chihuahua is 6.6 m/s².

Finally, we shall determine the force need to stop the Chihuahua as shown below:

Mass of Chihuahua (m) = 3.63 kg

Acceleration (a) = 6.6 m/s².

Force (F) =?

F = ma

F = 3.63 × 6.6

F = 23.96 N

Therefore, a force of 23.96 N is needed to stop the Chihuahua.

8 0
2 years ago
Read 2 more answers
Nicolas is playing with his toy car. A parachute in the back of the car is released to help slow down the car.
natima [27]

Answer:3 N —->

Explanation:

4 0
3 years ago
Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the
Alex787 [66]

We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

<em />

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is <u>due to the motion of the observer or the source of the frequency (or both).</u>

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

While if you move away from the string, the opposite happens, and you will hear a "lower" sound.

Then the only thing that impacts in how we perceive the frequency is our velocity relative to the source.

So, why do observers A and B measure different frequencies?

The two correct answers are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

If you want to learn more, you can read:

brainly.com/question/17107808

6 0
2 years ago
A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t
salantis [7]

Answer:

2.07

Explanation:

Since you didn't supply the drawing, here is what I assumed:

A is the corner opposite the axis of rotation

B is one of the remaining two corners

L1 is the side between A & B

Centripetal acceleration is given by:

ac = v^2 / r = (v / r) * (v / r) * r…………1

Also angular speed is

w = v / r,………….2

Substituting (2) in (1) gives:

ac = (v / r) * (v / r) * r……….3

= (v / r)^2 * r

= w^2 * r

Therefore, the angular acceleration at A and at B are given by:

acA = w^2 * rA……..4

acB = w^2 * rB……..5

It is given that:

acA = n * acB…………6

Substituting (4) and (5) into (6) gives:

w^2 * rA = n * w^2 * rB ……….7==>

rA = n * rB……..8

In terms of the sides L1 and L2:

rA = sqrt (L1^2 + L2^2)…….9

and

rB = L2…………10

Considering (8):

n * L2 = sqrt (L1^2 + L2^2)………11

Squaring both sides:

n^2 * L2^2 = L1^2 + L2^2……….12

Dividing by L2^2:

n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13

= (L1 / L2)^2 + 1 ==>

n^2 - 1 = (L1 / L2)^2 ………14==>

L1 / L2 = sqrt (n^2 - 1) ………15

= sqrt (2.30^2 - 1)

= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30

8 0
2 years ago
A ball is thrown downward with an initial speed of 7 m / s. The ball's velocity after 3 seconds is m / s. (g = -9.8m / s²)
yan [13]

Answer:

-36.4 m/s

Explanation:

final velocity= initial velocity + acceleration x time

7 + (-9.8)(3)= -36.4 m/s

5 0
3 years ago
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