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Llana [10]
3 years ago
9

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound

of the ball hitting the pins 2.79 s after the ball is released from his hands.
Physics
1 answer:
pshichka [43]3 years ago
4 0

Let , speed of bowling ball is v .

Time taken by ball to hit the pins , t=\dfrac{16.5}{v} .

Speed of sound , u = 343 m/s .

Time taken by sound to reach ear , T=\dfrac{16.5}{343}=0.048\ s .

Now ,

Time taken by sound to hear after release :

2.79=\dfrac{16.5}{V}+0.048\\\\2.79-0.048=\dfrac{16.5}{V}\\\\2.742=\dfrac{16.5}{V}\\\\V=\dfrac{16.5}{2.742}\\\\V=6.02\ m/s

Hence , this is the required solution .

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