Question

A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound of the ball hitting the pins 2.79 s after the ball is released from his hands.

Answer 1

Let , speed of bowling ball is v .

Time taken by ball to hit the pins , $t=\dfrac{16.5}{v}$ .

Speed of sound , u = 343 m/s .

Time taken by sound to reach ear , $T=\dfrac{16.5}{343}=0.048\ s$ .

Now ,

Time taken by sound to hear after release :

$2.79=\dfrac{16.5}{V}+0.048\\\\2.79-0.048=\dfrac{16.5}{V}\\\\2.742=\dfrac{16.5}{V}\\\\V=\dfrac{16.5}{2.742}\\\\V=6.02\ m/s$

Hence , this is the required solution .