The speed of a wave in a uniform medium doesn't depend on its wavelength.
Answer:
b
Explanation:
the gravitational pull also helps with that but
The one that both benefits each other is the one I think it's mutalistic
Ideal Gas Law PV = nRT
THE GASEOUS STATE
Pressure atm
Volume liters
n moles
R L atm mol^-1 K^-1
Temperature Kelvin
pv = rt
divide both sides by v
pv/v = rt/v
p = rt/v
answer: p = rt/v
Ideal Gas Law: Density
PV = NRT
PV = mass/(mw)RT
mass/V = P (MW)/RT = density
Molar Mass:
Ideal Gas Law PV = NRT
PV = mass/(MW) RT
MW = mass * RT/PV
Measures of Gases:
Daltons Law of Partial Pressures; is the total pressure of a mixture of gases equals the sum of the partial pressures of the individual gases.
Total = P_ A + P_ B
P_ A V = n_ A RT
P_ B V = n_ B R T
Partial Pressures in Gas Mixtures:
P_ total = P_ A + P_ B
P_ A = n_ A RT/V P_ B = n_ B RTV
P_ total = P_ A + P_ B = n_ total RT/V
For Ideal Gasses:
P_ A = n_ A RT/V P_ total = n_ toatal RT/V
P_ A/P_ total = n_ A RTV/n_ total RTV
= n_ A/n_ total = X_ A
Therefore, P_ A = X_ A P_ total.
PV = nRT
P pressure
V volume
n Number of moles
R Gas Constant
T temperture (Kelvin.).
Hope that helps!!!!!! Have a great day : )
2.0 meters The skateboarder has 2 forces acting upon him to slow him down. The forces are friction, and climbing against the gravitational acceleration. So let's calculate the magnitude of these forces to see how fast he's decelerated. The coefficient of kinetic friction is a multiplier to use against the normal force of the object. We can calculate the normal force by multiplying the mass of the object by the local gravitational acceleration and the cosine of the angle. So Df = 60 kg * 9.8 m/s^2 * cos(20°) * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 165.7617783 kg*m/s^2 Df = 165.7617783 N
The second amount of force is that caused by gravitational acceleration while climbing. That is determine by the amount of height gained for every meter along the slope. We can calculate that using the sine of the angle. So
Dg = 60 kg * 9.8 m/s^2 * sin(20°)
Dg = 60 kg * 9.8 m/s^2 * 0.342020143
Dg = 201.1078443 kg*m/s^2
Dg = 201.1078443 N
So the amount of force decelerating the skateboarder is:
F = Df + Dg
F = 165.7617783 N + 201.1078443 N
F = 366.8696226 N
Now let's determine how much kinetic energy needs to be dissipated. The equation is
E = 0.5 MV^2
So we'll substitute the known values and calculate
E = 0.5 MV^2
E = 0.5* 60 kg * (5 m/s)^2
E = 0.5* 60 kg * 25 m^2/s^2
E = 750 kg*m^2/s^2
E = 750 J
Now let's divide the energy by the force.
750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
Rounding to 2 significant figures gives a distance of 2.0 meters.
