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elixir [45]
3 years ago
10

A hammer of mass M is moving at speed v0 when it strikes a nail of negligible mass that is stuck in a wooden block. The hammer i

s observed to drive the nail a distance L deeper into the block.
(a) Find the work W done on the hammer by the nail. Express your answer as a function of F and L, where F is the force the nail exerts on the hammer. Don't forget to consider the sign of your answer.
(b) Find the change in kinetic energy of the hammer. Express your answer in terms of M and v0.
(c) Find the magnitude F of the force that the wooden block exerts on the nail, assuming that this force is independent of the depth of penetration of the nail into the wood.
(d) Now evaluate the magnitude of the holding force of the wooden block on the nail by assuming that the force necessary to pull the nail out is the same as that needed to drive it in, which we just derived.
Assume a relatively heavy M = 0.5 kg hammer (about 18 ounces), moving with speed v0 = 10 m/s. (If such a hammer were swung this hard upward and released, it would rise 5 m). Take the penetration depth L to be 2 cm, which is appropriate for one hit on a relatively heavy construction nail. Express your answer to the nearest pound. (Note: 1 lb = 4:45 N.)
Physics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

i think it would be D

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Answer:

<em> The add mass = 5.465 kg</em>

Explanation:

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f ∝ √(1/m)........................ Equation 1  (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

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T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

<em>Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.</em>

<em>Substituting into equation 4</em>

<em>m₂ = (2.07)²(0.5)/(1.18)²</em>

<em>m₂ = 4.285(1.392)</em>

<em>m₂ = 5.965 kg.</em>

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

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<em>Thus the add mass = 5.465 kg</em>

7 0
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