Hey there!:
Molar mass of Mg(OH)2 = 58.33 g/mol
number of moles Mg(OH)2 :
moles of Mg(OH)2 = 30.6 / 58.33 => 0.5246 moles
Molar mass of H3PO4 = 97.99 g/mol
number of moles H3PO4:
moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles
Balanced chemical equation is:
3 Mg(OH)2 + 2 H3PO4 ---> Mg3(PO4)2 + 6 H2O
3 mol of Mg(OH)2 reacts with 2 mol of H3PO4 ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !
Now , we will use Mg(OH)2 in further calculation .
Molar mass of Mg3(PO4)2 = 262.87 g/mol
According to balanced equation :
mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2
= (1/3)*0.5246
= 0.1749 moles of Mg3(PO4)2
use :
mass of Mg3(PO4)2 = number of mol * molar mass
= 0.1749 * 262.87
= 46 g of Mg3(PO4)2
Therefore:
% yield = actual mass * 100 / theoretical mass
% = 34.7 * 100 / 46
% = 3470 / 46
= 75.5%
Hope that helps!
From,
RAM=element×its relative abudance/total abudance
=((107×13)+(12×109))/25
The answer is=107.96
<h3><u>Question</u> :-</h3>
- A car starts from rest and accelerates at 2.5m/s² for 2s. What is the final velocity of the car?
<h3><u>Required Solution </u>:-</h3>
- The final velocity of the car is 5 m/s
<h3><u>Provided that</u> :-</h3>
- Acceleration, a = 2.5m/s²
- Time taken, t = 2 sec
- Initial velocity, u = 0 m/s (As car started from rest)
<h3><u>To Calculate</u> :-</h3>
- The final velocity of the car
<h3><u>Required Equations of Motion </u>:-</h3>
![\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%5Cboxed%7B%5Cbegin%7Barray%7D%7Bc%7D%5C%5C%20%7B%5Cpmb%7B%5Csf%7BThree%20%5C%3A%20equation%20%5C%3A%20of%20%5C%3A%20motion%7D%7D%7D%20%5C%5C%20%5C%5C%20%5Csf%20%5Cstar%20%5C%3A%20v%20%5C%3A%20%3D%20u%20%5C%3A%20%2B%20at%20%5C%5C%20%5C%5C%20%5Csf%20%5Cstar%20%5C%3A%20s%20%5C%3A%20%3D%20ut%20%2B%20%5C%3A%20%5Cdfrac%7B1%7D%7B2%7D%20%5C%3A%20at%5E2%20%5C%5C%20%5C%5C%20%5Csf%20%5Cstar%20%5C%3A%20v%5E2%20-%20u%5E2%20%5C%3A%20%3D%202as%5Cend%7Barray%7D%7D%5Cend%7Bgathered%7D)
<h3><u>Calculation</u> :-</h3>
![\pink{\qquad \pmb{ \sf\longrightarrow v \: = u \: + at}}](https://tex.z-dn.net/?f=%5Cpink%7B%5Cqquad%20%5Cpmb%7B%20%5Csf%5Clongrightarrow%20v%20%5C%3A%20%3D%20u%20%5C%3A%20%2B%20at%7D%7D)
![\qquad \pmb{\sf \longrightarrow v = 0 + 2.5 \times 2}](https://tex.z-dn.net/?f=%20%20%5Cqquad%20%5Cpmb%7B%5Csf%20%5Clongrightarrow%20v%20%3D%200%20%2B%202.5%20%5Ctimes%202%7D)
![\qquad \pmb{ \sf\longrightarrow v = 0 + 5}](https://tex.z-dn.net/?f=%5Cqquad%20%5Cpmb%7B%20%5Csf%5Clongrightarrow%20%20v%20%3D%200%20%2B%205%7D)
![\qquad \pmb{\sf \longrightarrow v = 5 \: ms^{-1}}](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Cpmb%7B%5Csf%20%5Clongrightarrow%20v%20%3D%205%20%5C%3A%20ms%5E%7B-1%7D%7D)
![\qquad \longrightarrow {\pink{\underline{\underline{\pmb{\sf{ Final \: velocity= 5 \: ms^{-1} }}}}}}](https://tex.z-dn.net/?f=%5Cqquad%20%5Clongrightarrow%20%7B%5Cpink%7B%5Cunderline%7B%5Cunderline%7B%5Cpmb%7B%5Csf%7B%20%20Final%20%5C%3A%20velocity%3D%20%205%20%5C%3A%20ms%5E%7B-1%7D%20%7D%7D%7D%7D%7D%7D)
<u>Henceforth</u> –
- The final velocity of the car is 5 m/s
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Am so pro let it goo let it goooo