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aleksandrvk [35]
2 years ago
8

What's the (snowy sour) mixture?​

Chemistry
2 answers:
hichkok12 [17]2 years ago
8 0

CH6COOH

Vinegar pickles

navik [9.2K]2 years ago
7 0
The Story Behind The Snowy Sour
As the air gets cooler and winter creeps in, I’m looking forward to the first snowfall of the season. This cocktail is all you will need to help you through. I took a classic sour cocktail and elevated it with a winter-citrus-infused simple syrup, made by combining clementine, orange, and honey with sugar and water. All the flavors came together really well, and the gin and fresh lemon juice amalgamate beautifully.

Ingredients In The Snowy Sour:

1.5 ounces gin
1 ounce lemon juice
¾ ounce winter citrus syrup
1 egg white
Snowy Sour Directions:

Combine all ingredients in a cocktail shaker with ice.
Shake hard to chill and combine.
Strain out ice.
Shake hard again to create a silky consistency.
Finely strain into your cocktail glass.
Garnish and enjoy!
Winter Citrus Simple Syrup Ingredients:
2 ounces clementine juice
2 ounces orange juice
2 ounces honey
2 ounces sugar
1 cup water
Winter Citrus Simple Syrup Directions:
Combine all ingredients into a small saucepan.
Bring to a boil.
Remove from heat element and stir while cooling.
Allow to sit for 30 minutes to an hour.
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For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
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Answer:

Explanation:

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The oxidation number of K in KClO₂:

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The oxidation number of K in KCl:

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The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

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