All categories

2 years ago

What are the properties of carbon dioxide?

1 answer:

mihalych1998 [28]2 years ago

6 0

The property of carbon oxide are the gas is odorless at low concentration and at high concentration have a Sharp acidic order .At standard Temperature and Pressure the density of carbon dioxide is 1.98kg/m3 at about 1.67 times that of air

You might be interested in

To make a 1.0L dilute of 0.5M from a stock solution of 12M, how much solution will be needed?

Cerrena [4.2K]

Answer:

$V_{concentrated}=0.042L=4.2mL$

Explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

$M_{diluted}V_{diluted}=M_{concentrated}V_{concentrated}$

Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:

$V_{concentrated}=\frac{M_{diluted}V_{diluted}}{M_{concentrated}} =\frac{0.5M*1.0L}{12M}\\ \\V_{concentrated}=0.042L=4.2mL$

Best regards.

6 0

3 years ago

The colligative molality of an unknown aqueous solution is 1.56 m.

yawa3891 [41]

Answer:

Vapor pressure of solution = 17.02 Torr

T° of boiling point for the solution is 100.79°C

T° of freezing point for the solution is -2.9°C

Explanation:

Let's state the colligative properties with their formulas

- Vapor pressure lowering

ΔP = P° . Xm . i

- Boiling point elevation

ΔT = Kb . m . i

- Freezing point depressión

ΔT = Kf . m . i

ΔP = Vapor pressure pure solvent (P°) - Vapor pressure solution

ΔT = T° boling solution - T° boiling pure solvent

ΔT = T° freezing pure solvent - T° freezing solution

i represents the Van't Hoff factor (ions dissolved in the solution). If we assume that the solute is non-volatile and the solution is ideal i = 1

Kf and Kb are cryoscopic and ebulloscopic constant, they are specific to each solvent.

Vapor pressure works with mole fraction (Xm) and the only data we have is molality, so we consider 1.56 moles of solute and 1000 g of solvent mass.

Moles of solvent → solvent mass / molar mass of solvent

Moles of solvent → 1000 g / 18 g/mol = 55.5 moles

Mole fraction is moles of solute / Total moles (mol st + mol sv)

Mole fraction: 1.56 / (1.56 + 55.5) = 0.027

- Vapor pressure lowering

ΔP = P° . Xm . i

17.5 Torr - Vapor pressure of solution = 17.5 Torr . 0.027 . 1

Vapor pressure of solution = - (17.5 Torr . 0.027 . 1 - 17.5 Torr)

Vapor pressure of solution = 17.02 Torr

- Boiling point elevation

ΔT = Kb . m . i

T° boiling solution - 100° = 0.512 °C/ m . 1.56 m . 1

T°boiling solution = 0.512 °C/ m . 1.56 m . 1 + 100°C

T°boiling solution = 100.79°C

- Freezing point depression

ΔT = Kf . m . i

0°C - T° freezing solution = 1.86 °C/m . 1.56 m . 1

T° freezing solution = - (1.86 °C/m . 1.56 m)

T° freezing solution = -2.9°C

3 0

3 years ago

How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?

Andreas93 [3]

Answer:

Two electrons.

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or $1s^22s^22p^63s^23p^64s^2$

There are 2 valence electrons of Calcium.

Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or $[Kr]4d^{10}5s^25p^5$

There are 7 valence electrons of iodine.

Calcium iodide, $CaI_2$ is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.

7 0

3 years ago

Conclusion

Natalija [7]

whats the question?

8 0

2 years ago

In the hydrologic cycle, water from the ocean into the atmosphere where it can and change back into tiny water droplets.

Alex

Hmmmm that’s a question you just have to take the time to think about the more you think about it the more u will get it u can take as much time as u need

8 0

2 years ago