The lines graphed below are perpendicular. The slope of the red line is 4. What is the slope of the green line?

Please help....There are 42 boys and girls participating in an essay-writing competition. Of the competitors, 21 are in seventh

almond37 [142]

The probability of an 8th grader winning is : 14/42 which reduces to 1/3

the simulation would be : # 3 <====

because u will have 6 equal sections on ur spinner...with each section representing 7 people
one section representing 9th graders...so their is 7 of them
2 sections representing 8th graders....so their is 7 * 2 = 14 of them
and 3 sections representing 7th graders....7 * 3 = 21 of them

7 0

3 years ago

Read 2 more answers

Rewrite 1 11/25 and 3 3/8 as a square or cube. PLEASE PLEASE PLEASE HALLLLLPP, looool

GrogVix [38]

1 11/25

= 36/25 = (6/5)^2

and

3 3/8

= 27/8 = (3/2)^3

5 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago

The probability that a civil servant own a car is 1/6,if two civil servants are selected at random.find the probability that

Elodia [21]

Answer:

The data we have is:

the probability that a civil servant own a car is 1/6

Two civil servants are selected at random.

a) The probability that each own a car.

Ok, here we have two events:

Person 1 haves a car.

Person 2 haves a car.

The probability of each of those events is the same, 1/6.

P1 = 1/6

P2 = 1/6

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities.

P = P1*P2 = (1/6)*(1/6) = 1/36.

b) Only one has a car.

Suppose that Person 1 has the car and Person 2 has not a car.

The probability for person 1 is 1/6.

And for person 2, is the negation of having a car:

So if we have prob of having a car = 1/6

Then the probability of not having a car is = 1 - 1/6 = 5/6.

Then we have:

P1 = 1/6

P2 = 5/6.

The joint probability is:

P = P1*P2 = (1/6)*(5/6) = 5/36.

But we also have the case where person 1 does not have a car, and person 2 does have one, then we have a permutation, and the actual probability is two times the obtained above.

P = 2*(5/36) = 10/36

4 0

3 years ago

Which expression is equivalent to

viva [34]

Answer:

C) $x^{27} (\sqrt[3]{y} )$

Step-by-step explanation:

8 0

3 years ago