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sleet_krkn [62]
4 years ago
6

Isaac drop ball from height og 2.0 m, and it bounces to a height of 1.5 m what is the speed before and after the ball bounce?

Physics
1 answer:
klasskru [66]4 years ago
6 0

Explanation:

It is given that, Isaac drop ball from height of 2.0 m, and it bounces to a height of 1.5 m.

We need to find the speed before and after the ball bounce.

Let u is the initial speed of the ball when he dropped from height of 2 m. The conservation of energy holds here. So,

\dfrac{1}{2}mu^2=mgh\\\\u=\sqrt{2gh} \\\\u=\sqrt{2\times 9.8\times 2} \\\\u=6.26\ m/s

Let v is the final speed when it bounces to a height of 1.5 m. So,

\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 1.5} \\\\v=5.42\ m/s

So, the speed before and after the ball bounce is 6.26 m/s and 5.42 m/s respectively.

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A condition in which self molecules are treated as non-self is the best definition of autoimmune disease.

<u>Option: D</u>

<u>Explanation:</u>

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3 years ago
A car, a bicycle, a bus, and a motorcycle are moving parallel to each other on a road. Each vehicle is traveling at the same spe
Olin [163]
The BUS will have the highest kinetic energy, while the BICYCLE will have the lowest kinetic energy.

This is because if an object has a greater mass, the kinetic energy of the object also increases. Kinetic energy depends on mass and velocity (KE=1/2*m*v^2) and since the velocity of these vehicles are the same, the mass is the only difference
4 0
4 years ago
A man walks 600 m [E47°N], then 500 m [N38°W], then 300 m [W29°S], and finally 400 m [S13°E]. Find his resultant displacement.
Archy [21]

The horizontal component of an angular distance can be calculated by multiplying the distance with the cosine of the angle, Dx = D * cos θ

While the vertical component is calculated by multiplying the distance with the sine of the angle, Dy = D * sin θ

The resultant displacement can then be obtained using the formula for hypotenuse and summations of each component:

R^2 = (summation of Dx)^2 + (summation of Dy)^2

summation of Dx = 600 * cos47 + 500 * cos128 + 300 * cos209 + 400 * cos(-77) = -71.0372

summation of Dy = 600 * sin47 + 500 * sin128 + 300 * sin209 + 400 * sin(-77) = 297.6267

<span>                        Note: you have to draw the lines to correctly determine the angles</span>

R^2 = (-71.0372)^2 + 297.6267^2

R = 306 m

The resultant angle is:

tan θ = Dy / Dx

θ = tan^-1 (297.6267 / -71.0372)

θ = 103˚ = [N 13˚ W]

Therefore displacement is 306 m <span>[N 13˚ W].</span>

4 0
4 years ago
Hi please zoom in to see it clearly, uh you don’t have to answer them all but it would be nice !!! (no links please) :D
kap26 [50]
12.could be D
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3 0
3 years ago
A ball of mass 24.1 g is attached to a cord of length 0.417 m and rotates in a vertical circle. What is the minimum speed the ba
Karo-lina-s [1.5K]

Answer:

<em>the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

<em></em>

Explanation:

In order to avoid slack, the centripetal force of the ball must equal its weight at the top of the circle. Therefore,

F_c = F_g

m v² / r = m g

v² = g r

v = √[g r]

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<em>v = 2.02 m/s </em>

Therefore,<em> the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

6 0
3 years ago
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