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sleet_krkn [62]
3 years ago
6

Isaac drop ball from height og 2.0 m, and it bounces to a height of 1.5 m what is the speed before and after the ball bounce?

Physics
1 answer:
klasskru [66]3 years ago
6 0

Explanation:

It is given that, Isaac drop ball from height of 2.0 m, and it bounces to a height of 1.5 m.

We need to find the speed before and after the ball bounce.

Let u is the initial speed of the ball when he dropped from height of 2 m. The conservation of energy holds here. So,

\dfrac{1}{2}mu^2=mgh\\\\u=\sqrt{2gh} \\\\u=\sqrt{2\times 9.8\times 2} \\\\u=6.26\ m/s

Let v is the final speed when it bounces to a height of 1.5 m. So,

\dfrac{1}{2}mv^2=mgh\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 1.5} \\\\v=5.42\ m/s

So, the speed before and after the ball bounce is 6.26 m/s and 5.42 m/s respectively.

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Consider the displacement vectors Ā=(i +6j)m, B = (3i– 7j)m,
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