Question

A bowling ball moving with a velocity of 5V to the right collides elastically with a beach ball moving at a velocity 2V to the left. The bowling ball barely slows down. What is the approximate velocity of the beach ball after the collision?

Answer 1

Answer:

$v'_2=3V$

Explanation:

From the question we are told that:

Bowling ball Speed $v_1=5 m/s$

Beach ball Speed $v_2=2 m/s$

Let The Mass be equal i.e

 $M_1=M_2$

Therefore

Generally the equation for Velocity of beach ball after collision $v'_2$ is mathematically given by

Since Velocity is Vector Quantity

Therefore

 $v'_2=v_1-v_2$

 $v'_2=5-2$

 $v'_2=3V$